Mean Value Theorem Formula

In mathematics, the mean value theorem states, roughly, that given a planar arc between two endpoints, there is at least one point at which the tangent to the arc is parallel to the secant through its endpoints.

The Mean Value Theorem states that if f(x) is continuous on [a,b] and differentiable on (a,b) then there exists a number c between a and b such that:

\[\large {f}'(c)=\frac{f(b)-f(a)}{b-a}\]

Solved Examples

Question 1: Evaluate f(x) = x+ 2 in the interval [1, 2] using mean value theorem ?


Given function is
f(x) = x+ 2 and the interval is [1,2]

Mean value theorem is given by,

f'(c) = $\frac{f(b)-f(a)}{b-a}$

f(b) = f(2) = 22 + 2 = 6

f(a) = f(1) = 12 + 2 = 3

So, f'(c) = $\frac{6-3}{2-1}$ = 3



Practise This Question

Let a=a1^i+α2^j+a3^k, b=b1^i+b2^j+b3^k and c=c1 ^i+c2 ^j+c3 ^k be three non-zero vectors such that c is a unit vector perpendicular to both the vectors a and b. If the angle between a and b is π6,
then ∣ ∣a1a2a3b1b2b3c1c2c3∣ ∣2 is equal to