The point at which the two coordinate axes meet is called the A. abscissa B. ordinate C. origin D. quadrant
The correct answer is C. origin Solution Origin: The coordinate axes intersect each other at right angles, The point of... View Article
Latest Posts
Ordinate of all points on the x-axis is A. 0 B. 1 C. – 1 D. any number
The correct answer is A. 0 Solution The abscissa and ordinate are used to represent the position of a point... View Article
Abscissa of all the points on the x-axis is (A) 0 (B) 1 (C) 2 (D) any number
Answer: (D) any number The abscissa of all the points on the x-axis can be any number. The abscissa and ordinate... View Article
Point (- 10, 0) lies A. on the negative direction of the x-axis B. on the negative direction of the y-axis C. in the third quadrant D. in the fourth quadrant
The correct answer is A. on the negative direction of the x-axis Solution The abscissa and ordinate are used to represent... View Article
Point (0, -7) lies A. on the x -axis B. in the second quadrant C. on the y-axis D. in the fourth quadrant
The correct answer is C. on the y-axis Solution The coordinates of the X-axis on the cartesian plane is called... View Article
Signs of the abscissa and ordinate of a point in the second quadrant are respectively A. + , + B. -, – C. -, + D. + , –
The correct answer is C. –, + Solution In Quadrant 2 Co-ordinate Plane the points are in the form: (-x,... View Article
Point (-3, 5) lies in the A. first quadrant B. second quadrant C. third quadrant D. fourth quadrant
The correct answer is B. second quadrant Solution In Quadrant 2 Co-ordinate Plane the points are in the form: (-x, +y)... View Article
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
Given f(x) = 2x4 – 5x3 + 2x2 – x + 2 To Prove 2x4 – 5x3 + 2x2 – x + 2 is divisible by... View Article
If both x – 2 and x – 1/2 are factors of px2 + 5x + r, show that p = r.
Given f(x) = px2+5x+r and factors are x-2, x – 1/2 To Prove We have to prove that p = r..... View Article
The polynomial p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by x + 1 leaves the remainder 19. Find the values of a. Also find the remainder when p(x) is divided by x + 2.
Given p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by x + 1 leaves the remainder 19 Find out We have to... View Article
If the polynomials az3 + 4z2 + 3z – 4 and z3 – 4z + a leave the same remainder when divided by z – 3, find the value of a.
Given p(z)=az3 + 4z2 + 3z – 4 p1(z)= z3 – 4z + a on dividing by z – 3 leave the same reminder... View Article
If + 2 is a factor of 5 – 4 2 3 + 2 + 2 + 3, find a.
Solution According to the given details Let p(x) = x5 – 4a2x3 + 2x + 2a + 3 g(x) = x + 2a g(x) = 0... View Article
For what value of m is 3 – 2 2 + 16 divisible by x + 2?
Solution According to the given details Let p(x) = x 3 – 2mx2 + 16, g(x) = x + 2 g(x) = 0 ⟹ x +... View Article
Show that p – 1 is a factor of p10 – 1 and also of p11 – 1.
Solution Let f(p) = 10 − 1,and m(p) = – 1 zero of m(p) ⇒ m(p) = 0 p – 1 =... View Article
Determine which of the following polynomials has x – 2 a factor: (i) 3 2 + 6 −24. (ii) 4 2 + −2.
Solution (i) 3 2 + 6 −24. Let p(x) =3 2 + 6 −24 g(x) = x – 2 g(x) = x... View Article
Show that: (i) + 3 is a factor of 69 + 11 − 2 + 3. (ii) 2 −3 is a factor of + 2 3 – 9 2 + 12
Solution (i) + 3 is a factor of 69 + 11 − 2 + 3. Let us assume that p(x) =... View Article
Check whether p( ) is a multiple of g( ) or not: (i) p( ) = 3 – 5 2 + 4 – 3, g( ) = – 2 (ii) p( ) = 2 3 – 11 2− 4 + 5, ( ) = 2 + 1
Solution (i) p( ) = 3 – 5 2 + 4 – 3, g( ) = – 2 According to the given... View Article
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where (i) p( ) = 3 – 2 2 – 4 – 1, g( ) = + 1 (ii) p( ) = 3 – 3 2 + 4 + 50, g( ) = – 3 (iii) p( ) = 4 23 – 12 2 + 14 – 3, g( ) = 2 – 1 (iv) p( ) = 3 – 6 2 + 2 – 4, g( ) = 1 – 3/2
Solution The remainder theorem says that if a polynomial p(x) is divided by a linear factor (x-a) then the remainder... View Article
By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x4 + 1; x -1
Solution On performing the long division method to the given polynomial x4 + 1 by x-1 we obtain Hence, Quotient = x3 +... View Article
Find the zeroes of the polynomial: p( ) = ( -2)2−( + 2)2
Solution p(x) = ( –2)2−( + 2)2 Zero of the polynomial p(x) = 0 Hence, ⇒ (x–2)2−(x + 2)2 = 0 On expanding... View Article
