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Find the moment of inertia for a badminton racket about an axis passing through ‘A’ and perpendicular to the plane as shown in the figure. Mass of the circular portion is M and that of the straight is

a. \(\begin{array}{l}\frac{173Mr^{2}}{4}+\frac{37mr^{2}}{4}\end{array} \) b. \(\begin{array}{l}-\frac{173Mr^{2}}{4}+\frac{37mr^{2}}{4}\end{array} \) c. \(\begin{array}{l}\frac{173mr^{2}}{4}+\frac{37Mr^{2}}{4}\end{array} \) d. \(\begin{array}{l}-\frac{173mr^{2}}{4}+\frac{37Mr^{2}}{4}\end{array} \) Solution: Answer: (a)