# An amplitude modulated wave is represented by, Cm = 10(1 + 0.2sin12560t)sin(1.11 × 104t) V the modulating frequency in kHz will be

Solution:

As we know that,

$$C_{m}= A_{c}\left [1+\frac{A_{m}}{A_{c}}sin2\pi f_{m}t \right ]$$

⇒ 2πfm = 12560

fm = 2000 Hz = 2 kHz