An amplitude modulated wave is represented by, Cm = 10(1 + 0.2sin12560t)sin(1.11 × 104t) V the modulating frequency in kHz will be

Solution:

Answer: 2 kHz

As we know that,

\(C_{m}= A_{c}\left [1+\frac{A_{m}}{A_{c}}sin2\pi f_{m}t \right ]\)

⇒ 2πfm = 12560

fm = 2000 Hz = 2 kHz

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