Get Answers for All Your JEE Questions

JEE Questions

Welcome to the BYJU’S JEE questions and answers page! Students and aspirants can access a huge library of questions covering all the important topics that are included in the JEE syllabus. The questions and answers have been prepared by a group of experienced subject matter experts. Students will find questions framed from Physics, Maths and Chemistry subjects.

The JEE questions and answers discussed here will give a much clearer idea of many JEE topics such as gravitation, thermodynamics, atomic structure, chemical bonding, binomial theorem, quadratic equation, etc. The questions have further been answered in an informative and easy to understand manner.

Alternatively, the questions are very important from an examination point of view and can help in quick revision of the different topics. Additionally, students can also clear their doubts and confusion by referring to these questions regarding any concept or topic. Students will find questions that are both conceptual and descriptive including definitions, principles, formulas, examples of, properties of, and types.

Featured Videos

How to draw a graph of Quadratic Polynomial

Newton's Second Law of Motion

Energy Change in Bond Formation

Free Body Diagram

All your doubts will be answered

Book a Free Class
Answer: 1) 3 2) –2 3) –3 4) 2 Solution: (3) –3 s = t3 – 3t2 ds / dt = v = 3t2 - 6t d2s / dt2 = a = 6t - 6 a = 0 6t - 6 = 0 t = 1 v = 3t2 - 6t = 3 (1)2 - 6 (1) = 3 - 6 = - 3 m/s...
Answer: 1) velocity 2) (velocity)3/2 3) (velocity)3 4) (velocity)2 Solution: (3) (velocity)3 s = √t = t1/2 v = ds / dt = (1 / 2) t-½ a = d2s / dt2 = (1 / 2) (- 1 / 2) t-3/2 = ( -...
Answer: 1) (9 / 8, 9 / 2) 2) (2, - 4) 3) (- 9 / 8, 9 / 2) 4) (2, 4) Solution: (1) (9 / 8, 9 / 2) y2 = 18x dy / dt = 2 (dx / dt) 2y (dy / dt) = 18 (dx / dt) y = 9 / 2, x = y2 / 18 = 81 /...
Answer: 1) (1 / 54π) cm/min 2) (5 / 6π) cm/min 3) (1 / 36π) cm/min 4) (1 / 18π) cm/min Solution: (4) (1 / 18π) cm/min dV / dt = 50 cm3/min (d / dt) [(4 / 3) πr3] = 50 3r2 (dr / dt) = [50...
Answer: 1) (1 / 30π) ft/min 2) (1 / 15π) ft/min 3) (1 / 20) ft/min 4) (1 / 25) ft/min Solution: (1) (1 / 30π) ft/min dV / dt = 30 ft3/min and r = 15ft V = (4 / 3) πr3 dV / dt = 4πr2...
Answer: 1) a 2) – a 3) 4b 4) – 4b Solution: (4) – 4b s = a sin t + b cos 2t ds / dt = a cost - 2b (sin 2t) d2s / dt2 = - a sint - 4b cos 2t At t = 0, d2s / dt2 = 0 - 4b = - 4b...
Answer: 1) 63 2) 104 3) 134 4) 288 Solution: (3) 134 S = 6 + 48t – t3 v = dS / dt = 0 + 48 − 3t2 When direction of motion reverses, v = 0 48 − 3t2 = 0 ⇒ t = −4, 4 (S)4 = 6 + 192−...
Answer: 1) 22 / 7 2) 22 3) 7 / 22 4) None of these Solution: (3) 7 / 22 dv / dt = 900 cm3/sec Volume of sphere = (4 / 3) πr3 dv / dt = d (4 / 3 πr3) / dt dv / dt = 4 / 3 π (d (r3)) /...
Answer: 1) Is constant 2) Varies as the distance from the axis of y 3) Varies as the distance from the axis of y 4) Varies as the distance of the point from the origin Solution: (3) Varies as...
Answer: 1) As the square of the perimeter 2) Inversely as the perimeter 3) As the radius 4) Inversely as the radius Solution: (3) As the radius P = 2πr A = πr2 dP / dt = 2π (dr / dt)...
Testimonials

Shikhar Mundra | AIR 20 - JEE Advanced 2020 |

The BYJU'S App was the first place I would go to, whenever I had any doubts in any concept. It was an integral part of my JEE preparation. The daily practice problems helped me revise and strengthen my concepts along with increasing my speed and accuracy.

Kunal Kundwani | AIR 63 - JEE Advanced 2020 |

The videos on the BYJU'S App aided in improving my weak areas in Chemistry. It was helpful in my preparation and I got to learn concepts in a different way. Practicing the mock tests and the AITS, along with the extensive analysis helped me identify my weak and strong areas.