Maths Questions

Maths is quite an abstract subject, and it can be rather intimidating at times. However, you can learn mathematics easily and effortlessly if you practice enough. To guide you in this endeavour, we have provided detailed solutions on many important concepts. The solutions are elaborated with simple, yet detailed explanations. Relevant formulas are listed out wherever required. Tips and shortcuts are provided to save precious time and effort.

Content is presented in a format which can be comprehended with ease. This means students will understand concepts without much hassle. From an exam perspective, a wide range of questions is covered from a plethora of subjects concepts from Trigonometry and Statistics to Calculus and Integrals.

Just like any other subject, mathematics can be better understood through exhaustive practice. Consider this analogy: a skill such as dancing or painting can only be perfected with enough practice. Similarly, the only way to get better at math is to keep practising. Moreover, we have a database of questions extracted from school textbooks and competitive exams. These will help the students to practice and perfect concepts in mathematics.

We are also here to help you solve your doubts. Post your questions in the comment box below and we will immediately provide answers and a detailed step-by-step process to solve the same. Register at BYJU’S and start practising Maths Questions today!

The volume of cuboid is the product of length, breadth, and height. Therefore, volume of cuboid = (l x b x h) cubic units. When the sides are
Let the two triangles be abc and pqr. So the ratio of areas of these two triangles will be square of ratio of perimeter. Therefore, the ratio of
During addition, the result cannot have more digits to the right of the decimal point than either of the original numbers. Since there is only 1
53 – 32 – 1 = 20 There are 20 whole numbers between 32 and53.
The Latin word commonly used for the digit 9 is “enn”. It is abbreviated as “e”.
Let the number be x. Given: 9/7 × x = 63 x = 63 × 7/9 x = 7 × 7 x = 49 Hence, the number is 49.
To stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? Solution:  Cloth
(a) Factors of 4 = 1, 2, 4 Factors of 8 = 1, 2, 4, 8 Factors of 12 = 1, 2, 3, 4, 6, 12 Common factors of 4, 8 and 12 = 1, 2, 4 (b) Factors of 5 =

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