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Find the principal value of tan-1 (- √3).

The principal value of tan-1 (- √3) is as follows. \(\begin{array}{l}=\tan ^{-1}\left(-\tan \frac{\pi}{3}\right)\\ \tan (-\theta)=-\tan \theta\\ =\tan ^{-1}\left(\tan \left(-\frac{\pi}{3}\right)\right)\\ =-\frac{\pi}{3}\end{array}... View Article

Evaluate sin-1 (sin 2).

The given expression is sin-1 (sin 2). \(\begin{array}{l}\Rightarrow \sin ^{-1}(\sin \theta)=\theta, \text { If }\left(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\right) \\... View Article