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Solve it (1 + i)-3.

The given expression is \(\begin{array}{l}\Rightarrow \frac{1}{(1+i)^{3}}\\=\frac{1}{1+i^{3}+3 i^{2}+3 i} \\ =\frac{1}{1-i-3+3 i} \\ =\frac{1}{-2+2 i}\\=\frac{1}{(2-2 i)} \\ =-(2+2 i)\end{array} \)