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Prove that 7 log (16 / 15) + 5 log (25 / 24) + 3 log (81 / 80) = log 2.

  Answer: \(\begin{array}{l}7 \log \left(\frac{16}{15}\right)+5 \log \left(\frac{25}{24}\right)+3 \log \left(\frac{81}{80}\right) \\ =\log \left[\left(\frac{16}{15}\right)^{7} \cdot\left(\frac{25}{24}\right)^{5} \cdot\left(\frac{81}{80}\right)^{3}\right] \\ =\log \left[\left(\frac{2^{4}}{3 \times 5}\right)^{7} \cdot\left(\frac{5^{2}}{2^{3}... View Article