# The Odometer Of The Car Reads 2000 Km At The Start Of The Trip And 2400 Km At The End Of The Trip. If The Trip Took 8 H, Calculate The Average Speed Of The Car In Kmh−1 And Ms−1.

Given:

The odometer of a car reads 2000 km. Let it be the initial distance

The odometer of a car reads 2400 km. Let it be the final distance.

Total distance covered = Final distance – Initial distance

= 2400 – 2000

= 400 km

As given in the question, the time taken = 8hours

The avergae speed =$$\frac{Total distance}{Total time taken}$$ $$\Rightarrow \frac{400}{8}$$ $$\Rightarrow 50 km/h$$

The average speed of the car in $$ms^{-1}$$is

$$1 km = 1000m \( 1 hour = 60 min = 3600 seconds \( 1 km/h = 5/18 m/s$$

Speed = 50 * $$\frac{5}{18}m/s$$ $$\Rightarrow \frac{250}{18}m/s$$ $$\Rightarrow 13.88m/s$$

Therefore,

The average speed of the car in $$Km h^{-1} 50 km/h$$

The average speed of the car in $$ms^{-1} is 13.88m/s$$

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