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Prove that sinA/1 + cosA = 1 – cosA / sinA

Solution: \(\begin{array}{l}\frac{sinA}{1+cosA}=\frac{1-cosA}{sinA}\end{array} \) Multiplying and dividing L.H.S by (1-cosA) \(\begin{array}{l}\frac{sinA}{1+cosA}\times \frac{1-cosA}{1-cosA}\end{array} \) \(\begin{array}{l}\frac{sinA\times (1-cosA))}{1-cos^{2}A}=\frac{1-cosA}{sinA}\end{array} \)