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Three blocks m, m and M are kept on a frictionless floor as shown in figure. The left most block is given velocity v towards right. All the collisions between the blocks are perfectly inelastic. The loss in kinetic energy after all the collisions is 5/6th of initial kinetic energy. The ratio of M/m will be:

a) 1/8 b) 1/4 c) 4 d) 2 Answer: (c) \(\begin{array}{l}\frac{mu}{2m+M}= V_{f}\end{array} \) \(\begin{array}{l}K_{f} = \frac{1}{6}K_{1}\end{array} \) \(\begin{array}{l}\frac{1}{2} \frac{P^{2}}{2m+M}= \frac{1}{6}\frac{1}{2}\frac{P^{2}}{m}\end{array}... View Article