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Question

Which of the following molecules is the least resonance stabilized?


A

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B

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C

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D

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Solution

The correct option is B


Stabilization of resonance
Resonance allows for delocalization, which lessens a molecule's overall energy since its electrons encompass a larger amount, allowing molecules that exhibit resonance more stable than those that do not. These compounds are classified as resonance stabilizing molecules.

Aromatic

Aromatic compounds feature conjugated planar benzene rings featuring delocalized pi-electron clouds because rather than separate alternating double and single bonds. Aromatics or arenes are several other names for them.

Huckel's 4n+2π Electron Rule.
A ring-shaped cyclic molecule is said to follow the Huckel rule when its total number of pi electrons can be equated to the formula '4n + 2', where n can be any positive integer (including zero).
Examples of molecules obeying Huckel's rule have only been found for 'n' values ranging from zero to six. The total number of pi electrons in the benzene molecule shown below is 6, following the 4n+2 electron rule where n=1.

The explanation for the correct option B(second molecule)

The component in option (B) seems to have the fewest number of resonance stabilization. Because the threre are no C=C double bonds are not part of the benzene ring, this is the scenario (i.e, they do not form alternate single and double bond systems in a ring system). As a function, this molecule lacks aromaticity.

The explanation for the incorrect options

  • The first molecule in option A is incorrect because it is aromatic
  • The third molecule in option C is incorrect because it is aromatic
  • The fourth molecule in option D is incorrect because it is aromatic

Conclusion

Option B molecule is absolutely correct answer.


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