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If every element of a group G is its own inverse, then G

1) Finite 2) Infinite 3) Cyclic 4) Abelian Solution: If every element of a group G is its own... View Article

1) 2 2) 3 3) Depends on the group 4) 1 Solution: In any group, the number of improper subgroups... View Article

1) all x 2) all negative real x not equal to 1 3) all positive real x not equal to... View Article

1) 1 2) -1 3) 2 4) -2 Solution: We use the remainder theorem. P(x) = x64 + x27... View Article

1) 2 2) 4 3) 9 4) 3 Solution: Given 3x – 3x-1 = 6 => 3x – 3x/3... View Article

1) 1/(x-1) – 3/(x-2) + 2/(x-3) 2) 1/(x-1) + 3/(x-2) + 1/(x-3) 3) -3/(x-1) + 1/(x-2) + 2/(x-3) 4) None... View Article

1) 3 + [49/2(x-4)] – [13/2(x-2)] 2) [49/2(x-4)] – 13/2(x-2) 3) -[49/2(x-4)] + 13/(x-2) 4) None of these Solution:... View Article

1) -1/2 2) 15/4 3) 7/4 4) -1/4 Solution: Given (3x+4)/(x+1)2(x-1) = A/(x-1) + B/(x+1) + C/(x+1)2 (3x+4)/(x+1)2(x-1) =... View Article

1) 4C 2) 4C + 1 3) 3C 4) 2C Solution: Given (x2 + x + 1)/(x2 + 2x... View Article

1) 5 2) 15 3) 16 4) 17 Solution: Given that p and q are prime numbers satisfying the... View Article

1) 0 2) 6 3) 4 4) none of these Solution: Given √(x+ 10) + √(x – 2) =... View Article

1) 400 2) 368 3) 200 4) none of these Solution: Given xy = 4 => y = 4/x ... View Article

1) 1 2) 2 3) 9/4 4) none of these Solution: Given (2x + 3)/(x + 1)(x – 3)... View Article

1) 0 2) 1 3) x + y + z + 2 4) x + y + z Solution:... View Article

1) 2xz/(x+z) 2) xz/2(x-z) 3) xz/2(z-x) 4) 2xz/(x-z) Solution: Let ax = by = cz = k So a... View Article

1) y 2) 2y 3) 2xyz 4) none of these Solution: Let a1/x = b1/y = c1/z = k... View Article

1) 0 2) 1 c) 2 4) 4 Solution: (2/3)x+2 = (3/2)2-2x (2/3)x+2 = (2/3)2x-2 => x + 2... View Article

1) x = 1, y = 8 2) x = 8, y = 1 3) x = 3, y =... View Article

1) 0 2) 1 c) 2 4) 4 Solution: Given x = logb a, y = logcb, z =... View Article

1) log a 2) log b c) 2 4) 1 Solution: Let a = n-1, b = n, c... View Article