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A glass prism of refracting angle 60° and refractive index 1.5 is completely immersed in water of refractive index 1.33. Calculate the angle of minimum deviation of the prism in this situation, sin-1 0.56 = 34.3°.

\(\begin{array}{l}^{Water}\mu _{lens}=\frac{\mu _{lens}}{\mu _{water}}\end{array} \) = 1.5/1.33 = (3/2)/(4/3) = 9/8 \(\begin{array}{l}\mu =\frac{Sin\frac{A+\delta _{m}}{2}}{Sin\frac{A}{2}}\\\frac{9}{8}=\frac{Sin\frac{60+\delta _{m}}{2}}{Sin 30}\\\frac{9}{16}= \left [ Sin\frac{60+\delta _{m}}{2}... View Article