In Fig.ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that: (i) ar (BDE) = 1/4 ar (ABC) (ii) ar (BDE) = 1/2 ar (BAE) (iii) ar (ABC) = 2 ar (BEC) (iv) ar (BFE) = ar (AFD) (v) ar (BFE) = 2 ar (FED) (vi) ar (FED) = 1/8 ar (AFC)
Solution i) Given: ABC and BDE are equilateral triangles D is mid point of BC i.e. BD=DC To prove: Proof: Let... View Article