Latest Posts

Match List-I with List-II:

Match List-I with List-II:   List-I List-II (a)h (Planck’s constant) (i) [MLT–1] (b)E (Kinetic energy) (ii) [ML2T–1] (c)V (Electric potential)... View Article

NISHTHA Scheme

The National Initiative for School Heads’ and Teachers’ Holistic Advancement (NISHTHA) is a capacity building programme for “Improving Quality of... View Article

If [latex]\vec{a}=\alpha i+\beta j+3k,\vec{b}=-\beta i-\alpha j-k \text \ and \ \vec{c}=i-2j-k,[/latex] such that[latex]\vec{a}.\vec{b}=1[/latex] and [latex]\vec{b}.\vec{c}=-3[/latex], then [latex]\frac{1}{3}((\vec{a}\times\vec{b}).\vec{c})=[/latex] is equal to

Answer: 2 \(\begin{array}{l}\\\vec{a}=(\alpha ,\beta, 3),\vec{b}=(-\beta,-\alpha,-1),\vec{c}=(1,-2,-1)\\ \vec{a}.\vec{b}=1\Rightarrow (-\alpha \beta -\alpha \beta -3)=1\\ -2\alpha \beta =4\\ \alpha \beta =-2\\ \vec{b}.\vec{c}=-3\Rightarrow (-\beta +2\alpha+1)=-3\\... View Article