The final major product of the following reaction is:
The final major product of the following reaction is: Answer: (3) Hence option 3 is the answer.
Latest Posts
The variation of molar conductivity with concentration of an electrolyte (X) in aqueous solution is shown in the given figure. The electrolyte X is:
1) HCl 2) CH3COOH 3) NaCl 4) KNO3 Answer: (2) Such type of variation is always for weak electrolyte.... View Article
The rate constant (k) of a reaction is measured at different temperatures
The rate constant (k) of a reaction is measured at different temperatures (T), and the data are plotted in the... View Article
The correct statement about probability density (except at infinite distance from nucleus) is :
1) It can be zero for 3p orbital 2) It can be zero for 1s orbital 3) It can never... View Article
The compound that has the largest H–M–H bond angle (M=N, O, S, C) is:
1) CH4 2) H2S 3) NH3 4) H2O Answer: (1) CH4 has the largest H-M-H bond angle.
Adsorption of a gas follows Freundlich adsorption isotherm
Adsorption of a gas follows Freundlich adsorption isotherm. If x is the mass of the gas adsorbed on mass m... View Article
Among the following compounds, geometrical isomerism
Among the following compounds, geometrical isomerism is exhibited by: Answer: (1 and 2)
The following molecule acts as an:
1) Anti-histamine 2) Antiseptic 3) Anti-depressant 4) Anti-bacterial Answer: (1) Bromopheniramine acts as an Anti-histamine.
Boron and silicon of very high purity can be obtained through:
1) Liquation 2) Electrolytic refining 3) Zone refining 4) Vapour phase refining Answer: (3) Boron and silicon of very high... View Article
Hydrogen peroxide, in the pure state, is:
1) Linear and blue in color 2) Linear and almost colorless 3) Non-planar and almost colorless 4) Planar and blue... View Article
The major product formed in the following reaction is:
1) CH3CH(Br)CH2CH(CH3)2 2) CH3CH2CH2C(Br)(CH3)2 3) CH3CH2CH(Br)CH(CH3)2 4) Br(CH2)3CH(CH3)2 Answer: (1) Option 1 is the answer.
Using the provided information in the following paper chromatogram:
Using the provided information in the following paper chromatogram: The calculated Rf value of A ______ × 10–1. Answer: 4... View Article
1 molal aqueous solution of an electrolyte A2B3 is 60% ionised. The boiling point of the solution at 1 atm is _____ K.
Answer: 375 K A2B3 → 2A+3 + 3B–2 No. of ions = 2 + 3 = 5 wi = 1... View Article
Among the following, the number of halide(s) which is/are inert to hydrolysis is ______
a. BF3 b. SiCl4 c. PCl5 d. SF6 Answer: 1 Due to crowding, SF6 is not hydrolyzed.
A car tire is filled with nitrogen gas at 35 psi at 27°C. It will burst if pressure exceeds 40 psi. The temperature in °C at which the car tyre will burst is ______. (Rounded-off to the nearest integer)
Answer: 69.85°C ≃ 70°C P1 / T1 = P2 / T2 35 / 300 = 40 / T2 T2 =... View Article
Consider the following chemical reaction.
Consider the following chemical reaction. The number of sp2 hybridized carbon atom(s) present in the product is _______. Answer: 7... View Article
The ionization enthalpy of Na+ formation from Na(g) is 495.8 kJ mol–1, while the electron gain enthalpy of Br is –325.0 kJ mol–1. Given the lattice enthalpy of NaBr is –728.4 kJ mol–1. The energy for the formation of NaBr ionic solid is (–)_____ × 10–1 kJ mol–1
Answer: 5576 kJ Na(s) → Na+(g) ΔH = 495.8 ½ Br2(λ) + e– → Br–(g) ΔH = 325 Na+(g) +... View Article
0.4g mixture of NaOH, Na2CO3 and some inert impurities was first titrated with N / 10HCl using phenolphthalein as an indicator, 17.5 mL of HCl was required at the end point. After this methyl orange was added and titrated. 1.5 mL of the same HCl was required for the next end point. The weight percentage of Na2CO3 in the mixture is ______. (Rounded-off to the nearest integer)
Answer: 3% 1st end point reaction NaOH + HCl → NaCl + H2O nf = 1 NaCO3 + HCl →... View Article
For the reaction, aA + bB → cC + dD, the plot of log k vs 1/T is given below:
The temperature at which the rate constant of the reaction is 10–4s–1 is ________ K. [Rounded off to the nearest... View Article
In basic medium CrO42– oxidizes S2O32– to form SO24 and itself changes into Cr(OH)4–. The volume of 0.154 M CrO42– required to react with 40 mL of 0.25 M S2O32– is ______ mL. (Rounded-off to the nearest integer)
Answer: 173 mL 17H2O + 8CrO4 + 3S2O3 → 6SO4 + 8Cr(OH)4– + 2OH– Applying mole-mole analysis 0.154 × v... View Article
