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A particle is projected vertically upwards from a point A on the ground. It takes time t1, to reach a point B, but it still continues to move up. It takes further time t2 to reach the ground from point B then height of point B from the ground is: (a) [latex]frac{1}{2}g(t_{1}+t_{2})^{2}[/latex] (b) [latex]gt_{1}t_{2}[/latex] (c) [latex]frac{1}{8}g(t_{1}+t_{2})^{2}[/latex] (d) [latex]frac{1}{2}gt_{1}t_{2}[/latex]

Given Total time of particle = (t1 + t2) To find initial value Applying 2nd equation of motion \(\begin{array}{l}0 =... View Article