If α and β are the roots of the equations x2 – (1 + n2) x+ 1 / 2 (1 + n2 + n4) = 0, then α2 + β2 is equal to
1) n2 2) – n2 3) n4 4) – n4 Solution: (1) n2 (α + β) = 1 + n2;... View Article
1) n2 2) – n2 3) n4 4) – n4 Solution: (1) n2 (α + β) = 1 + n2;... View Article
1) – a 2) b 3) 0 4) a – b Solution: (3) 0 If α, β are the roots... View Article
1) x2 – 18x – 16 = 0 2) x2 – 18x +16 = 0 3) x2 + 18x –... View Article
1) x2 + 2x – 16 = 0 2) x2 + 2x – 15 = 0 3) x2 + 2x... View Article
1) 7 2) 12 3) 18 4) 36 Solution: (3) 18 α + β + γ = 2 α2 +... View Article
1) 4 2) 1 3) 3 4) 2 Solution: (1) 4 |x|2 – 3 |x| + 2 = 0 (|x|... View Article
1) x3 – 4x – 1 = 0 2) x3 – 4x + 1 = 0 3) x3 + 4x... View Article
1) 32 2) 64 3) 128 4) 256 Solution: (3) 128 α + β = 2 αβ = 4 α2... View Article
1) β 2) π / 2 – β 3) π – β 4) – β Solution: (2) π / 2... View Article
1) 4/49 2) 49/4 3) 7/4 4) 4/7 Solution: (2) 49 / 4 It is given that 4 is the... View Article
1) ax2 + 3bx + 3c = 0 2) ax2 + 3bx + c = 0 3) 9ax2 + 9bx... View Article
1) 4 / (a + b) 2) 1 / (a + b) 3) 0 4) – 1 Solution: (3) 0... View Article
1) 80 2) 85 3) 90 4) 95 5) 100 Solution: (2) 85 The given equation is lx2 + mx... View Article
1) 45 2) 15 3) – 15 4) – 45 5) 25 Solution: (1) 45 Imaginary roots exist in conjugate... View Article
1) r 2) 2r 3) r 4) 1/r 5) 2/r Solution: (2) 2r 1 / (x + p) + 1... View Article
1) 4192 2) 4144 3) 4096 4) 4048 Solution: (4) 4048 (ɑ + β) = [ƛ – 1] / ƛ;... View Article
1) -2/3 2) -3 3) 4 4) -1/2 Solution: (1) -2 / 3 Let α and β be the roots... View Article
1) x2 – x + 1 = 0 2) x2 – x – 1 = 0 3) x2 + x... View Article
1) – 1 2) 0 3) 1 4) 2 5) 3 Solution: (3) 1 Let α, α + 1 are... View Article
1) 2 and -2 2) 2 and -1 3) 1 and – 2 4) 1 and 2 5) – 1... View Article