If x2 + px + q = 0 has the roots α and β, then the value of (α – β)2 is
1) p2 – 4q 2) (p2 – 4q)2 3) p2 + 4q 4) (p2 + 4q)2 Solution: (1) p2 –... View Article
1) p2 – 4q 2) (p2 – 4q)2 3) p2 + 4q 4) (p2 + 4q)2 Solution: (1) p2 –... View Article
1) – 4, 1 2) 4, -1 3) 2,√3 4) – 2, -√3 Solution: (1) – 4, 1 If 2... View Article
1) acx2 – bx + 1 = 0 2) x2 – acx + bc + 1 = 0 3) acx2... View Article
1) – 2 2) – 1 3) 1 4) 2 Solution: (3) 1 x2 – x + 1 = 0... View Article
1) (p3 + q)x2 – (p3 + 2q)x + (p3 + q ) = 0 2) (p3 + q)x2 –... View Article
1) -1 / 2 2) -1 3) 0 4) 1/2 Solution: (2) -1 x3 – x – x + 1... View Article
1) i2n+1 sin (nπ/3 ) 2) 2n+1 cos (nπ/3 ) 3) i 2n-1 sin (nπ/3 ) 4) 2n-1 cos (nπ/3... View Article
1) – 4 2) 1 3) 4 4) 0 Solution: (3) 4 Product = 31 2e2logk – 1 = 31... View Article
1) [(1 / ɑ) + (1 / √β)] and [(1 / ɑ) – (1 / √β)] 2) [(1 / √ɑ)... View Article
1) 2 2) 6 3) – 2 4) – 6 Solution: (4) – 6 x3 + 4x + 2 =... View Article
1) a2 + c2 = – ab 2) a2 – c2 = – ab 3) a2 – c2 = ab... View Article
1) b2 – 4ac 2) b2 – 2 ac 3) 2b2 – ac 4) ∑a2 Solution: (1) b2 – 4ac... View Article
1) x2 – 16 x – 25 = 0 2) x2 + 16 x – 25 = 0 3) x2... View Article
1) a2 + b2 = 2ac 2) b2 – c2 = 2ab 3) b2 – a2 = 2ac 4) b2... View Article
1) 0 2) abc 3) a + b + c 4) None of these Solution: (1) 0 α + β... View Article
1) there are infinite numbers of choices for a, b and c 2) only one choice for a but infinite... View Article
1) a2 : p2 2) a : p2 3) a2 : p 4) a : 2p Solution: (1) a2 :... View Article
1) – 1 and [loge c] / [loge a] 2) 1 and – [loge c] / [loge a] 3) 1... View Article
1) (α – β)2 / 4 2) (α + β)2 – αβ 3) (α + β)2 + αβ 4) [(α... View Article
1) -3/4 2) 3/4 3) -4/3 4) 4/3 5) 3/2 Solution: (2) 3 / 4 α + β = –... View Article