If Sin Inverse 2a 1 Plus A Square Plus Sin Inverse 2b
1) (a – b)/(1 + ab) 2) b/(1 + ab) 3) b/(1 – ab) 4) (a + b)/(1 – ab)... View Article
1) (a – b)/(1 + ab) 2) b/(1 + ab) 3) b/(1 – ab) 4) (a + b)/(1 – ab)... View Article
1) α + β 2) α – β 3) (1 + αβ)/(α + β) 4) (αβ – 1)/(α + β)... View Article
1) π/6 2) π/4 3) π/3 4) π/2 Answer: (2) π/4 Solution: Let sin-1(1/√5) = A sin A = 1/√5... View Article
1) 135° 2) 45° 3) 90° 4) 180° Answer: (1) 135° Solution: Given, x = 2, y = 3 As... View Article
1) 7/3 2) 3 3) 11/3 4) 13/3 Answer: (4) 13/3 Solution: Given, tan-1(1/3) + tan-1(3/4) – tan-1(x/3) = 0... View Article
1) π/4 2) π/2 3) π 4) 0 Answer: (2) π/2 Solution: Let x = tan A tan-1[(1 – x2)/2x]... View Article
1) π/3 2) π/4 3) π/6 4) π/2 Answer: (2) π/4 Solution: Let cosec-1(√5) = A cosec A = √5... View Article
1) 0 2) 1 3) -1 4) 2 Answer: (2) 1 Solution: Given, cos-1(3/5) – sin-1(4/5) = cos-1(x)….(i) Let sin-1(4/5)... View Article
1) 2√3a 2) √3a 3) 2√3a2 4) None of these Answer: (1) 2√3a Solution: Given, tan-1[(a + x)/a] + tan-1[(a... View Article
1) 0 2) 1 3) cot-1(x) + cot-1(y) + cot-1(z) 4) None of the above Answer: (1) 0 Solution: cot-1[(xy... View Article
1) tan-1(x2 + 1) 2) tan-1(x2 + x) 3) tan-1(x + 1) 4) tan-1(x2 + x + 1) Answer: (4)... View Article
1) 1/√2 2) √3/2 3) 1/2 4) π/4 Answer: (1) 1/√2 Solution: tan-1(1/3) + tan-1(1/2) Using the formula tan-1(x) +... View Article
1) π/2 2) 2π/3 3) 5π/3 4) None of these Answer: (1) π/2 Solution: Let 2 sin-1(3/5) = A sin-1(3/5)... View Article
1) 1/3 2) 1/4 3) 3 4) 4 Answer: (3) 3 Solution: Given, cot-1(x) + tan-1(3) = π/2 We know... View Article
1) x + y = 2 2) x + y = 1 3) x – y = 1 4) x2... View Article
1) 1 for all x > 2 2) 1 for 2 < x < 3 3) -1 for 2 <... View Article
1) a = b 2) a = 2b 3) a = 3b 4) a = 4b Solution: (4) a =... View Article
1) f (x) = [(1 / 2) – x), x < 1 / 2] 2) f (x) = sinx /... View Article
1) At least one root 2) At most one root 3) No root 4) Exactly one root exists Solution: (1)... View Article
1) |tan x| > 1 2) |tan x| < 1 3) 1 ≤ tan x < 1 4) -1 ≤... View Article