If X X 2 And G X F F X X 20 Then G Dash X
1) 1 2) 0 3) 9 4) 18 Solution: (1) 1 g (x) = f (f (x)) = |f (x)... View Article
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If X 2e Y 2xye X 23 0 Then Dy Dx
1) 2xey-x + 2y (x + 1) 2) 2xex-y – 3y (x + 1) 3) [2xey-x – 2y (x +... View Article
If F X Ax B And F 0 F X 2 Then F 1
1) 4 2) 2 3) 1 4) –4 Solution: (1) 4 f (x) = Ax + B f’ (x) =... View Article
If Y Cos N X Sinnx And Dy Dx N Cos N 1 X Cos B Then B
1) (n – 1) x 2) (n + 1) x 3) nx 4) (1 – n) x Solution: (2) (n... View Article
If A B C D Are Any Four Consecutive Coefficients Of Any Expanded Binomial Then
(1) AP (2) GP (3) HP (4) None of these Solution: We know (x+y)n = nC0xn + nC1xn-1y + nC2xn-2y2... View Article
Let A Be A Positive Number Such That The Arithmetic Mean Of A And 2 Exceeds Their Geometric Mean Be 1 Then The Value Of A Is
(1) 3 (2) 5 (3) 9 (4) 8 Solution: AM of a and 2 = (a+2)/2 GM of a and... View Article
If The Product Of Three Terms Of Gp If 512 If 8 Added To First And 6 Added To Second Term So That Number May Be In Ap Then The Numbers Are
(1) 2,4,8 (2) 4,8,16 (3) 3,6,12 (4) None of these Solution: Let a/r, a, ar be the terms in GP.... View Article
If A B C Are In Hp Then For All N N The True Statement Is
(1) an + cn < 2bn (2) an + cn > 2bn (3) an + cn = 2bn (4) None... View Article
When 1 A 1 C 1 A B 1 C B 0 And B Not Eq A C Then A B C Are In
(1) AP (2) GP (3) HP (4) None of these Solution: Given 1/a + 1/c + 1/(a-b) + 1/(c-b) =... View Article
If A Bx A Bx B Cxb Cx C Dx C Dx X 0 Then A B C D Are In
(1) AP (2) GP (3) HP (4) None of these Solution: Given (a+bx)/(a-bx) = (b+cx)/(b-cx) = (c+dx)/(c-dx) (a+bx)/(a-bx) = (b+cx)/(b-cx)... View Article
If X Plus Y By 2 Y Y Plus Z By 2 Are In Hp Then X Y Z Are In
(1) AP (2) GP (3) HP (4) None of these Solution: Given (x+y)/2, y, (y+z)/2 are in HP. So 2/(x+y),... View Article
If 9 Ams And Hms Are Inserted Between 2 And 3 And If The Harmonic Mean H Is Corresponding To Arithmetic Mean A Then A Plus 6 By H Is Equal To
(1) 1 (2) 3 (3) 5 (4) 6 Solution: Let A1,A2 …A9 are the AM’s and H1, H2, …H9 are... View Article
If A1 A2 Are Two Ams Between Two Numbers A And B And G1 G2 Be Two Gms Between Same Two Numbers Then A1 Plus A2 By G1g2
(1) (a+b)/ab (2) (a+b)/2ab (3) 2ab/(a+b) (4) ab/(a+b) Solution: Let a, A1, A2, b are in AP. Then (a+b)/2 =... View Article
If A And B Two Different Positive Real Numbers Then Which Of The Following Relation Is True
(1) 2√(ab) > (a+b) (2) 2√(ab) < (a+b) (3) 2√(ab) = (a+b) (4) none of these Solution: We know AM... View Article
The Value Of 1 By 1 Plus A By 2 Plus A Plus 1 By 2 Plus A By 3 Plus A Infinity Is Where A Is A Constant
(1) 1/(1+a) (2) 2/(1+a) (3) ∞ (4) None of these Solution: 1/(1+a)(2+a) + 1/(2+a)(3+a) + 1/(3+a)(4+a) +….. = 1/(1+a) –... View Article
If 1 By 1 4 Plus 1 By 2 4 Plus 1 By 3 4 Infinity Pi 4 90 Then The Value Of 1 By 1 4 Plus 1 By 3 4 Plus 1 By 5 4 Infinity Is
(1) π4/96 (2) π4/45 (3) 89 π4/90 (4) none of these Solution: Given 1/14 + 1/24 + 1/34 + 1/44... View Article
If Tn Eq 1 By 4 N Plus 2 N Plus 3 For N Eq 1 2 3 Then 1 T1 1 T2 1 T3 1 T2003
(1) 4006/3006 (2) 4003/3007 (3) 4006/3008 (4) 4006/3009 Solution: Given tn = (1/4)(n+2)(n+3) t1 = (1/4)(3×4) t2 = (¼)×4×5 t3... View Article
Four Numbers Are In Arithmetic Progression The Sum Of The First And Last Term Is 8 And The Product Of Both Middle Terms Is 15 The Least Number Of The Series Is
(1) 4 (2) 3 (3) 2 (4) 1 Solution: Let a-3d, a-d , a+d, a+3d are in AP. The sum... View Article
If A B C D E Are In Ap Then The Value Of A B 4c 4d E In Terms Of A If Possible Is
(1) 4a (2) 2a (3) 3 (4) None of these Solution: Given a,b,c,d,e are in A.P. Let D be the... View Article
If 1 Log9 3 1 X Plus2 Log3 4 3x 1 Are In Ap Then X Equals
(1) log3 4 (2) 1 – log3 4 (3) 1 – log4 3 (4) log4 3 Solution: Given 1, log9... View Article
