If The First And Nth Terms Of A Gp Are A And B Respectively And If P Is The Product Of The First N Terms Then P2 Is Equal To
(1) (an)n-1 (2) (an)n-2 (3) (an)n+1 (4) (ab)n Solution: Given first term of GP = a nth term = arn-1... View Article
Latest Posts
If The Non Zero Numbers X Y Z Are In Ap And Tan 1x Tan 1y Tan 1z Are In Ap Then
(1) x = y = z (2) xy = yz (3) x2 = yz (4) z2 = xy Solution: Since... View Article
1 Plus 2 By 1 2 3 Plus 2 By 3 4 5 Plus 2 By 5 6 7
(1) 2 log 2 (2) 2 log 4 (3) 2 log 3 (4) none of these Solution: log (1+x) =... View Article
1 By 1 2 Minus 1 By 2 3 Plus 1 By 3 4 1 By 4 5 Is
(1) 2 log 2 -1 (2) 3 log 2 (3) 4 log 2 – 1 (4) None of these Solution:... View Article
If G Is The Gm Of The Product Of R Set Of Observations With Geometric Means G1 G2 Gr Respectively Then G Is Equal To
(1) log G1 + log G2 + …log Gr (2) G1G2…..Gr (3) log G1.log G2….log Gr (4) none of these... View Article
9 By 1 Factorial Plus 19 By 2 Factorial Plus 35 By 3 Factorial To Infinity Is
(1) 12e (2) 12e-4 (3) 12e-3 (4) 12e-5 Solution: We use ex = 1 + x/1! + x2/2! + x3/3!... View Article
2 By 1 Factorial Plus 6 By 2 Factorial Plus 12 By 3 Factorial To Infinity Is
(1) 3e/2 (2) e (3) 2e (4) 3e Solution: S = 2/1! + 6/2! + 12/3! + 20/4! +…..∞ =... View Article
The Value Of 4 Plus 2 1 Plus 2 Log 2 Plus 2 Infinity
(1) 10 (2) 12 (3) log (32.42) (4) log (22.32) Solution: 4+2(1+2)log 2 + (2(1+22)/2!) (log 2)2 + (2(1+23)/3!)(log 2)3+…... View Article
The Sixth Term Of An Ap Is Equal To 2 And Its Common Difference Is Greater Than 1
(1) -8/5 (2) 8/5 (3) -5/8 (4) 5/8 Solution: Let a be the first term and d be the common... View Article
Number Of Terms In The Sequence 1 3 6 10 15 5050 Is
(1) 50 (2) 75 (3) 100 (4) 125 Solution: Given sequence 1, 3, 6, 10, 15,…., 5050 Let n be... View Article
If The M Plus 1 Th N Plus 1 Th And R Plus 1 Th Terms Of An Ap Are In Gp And
(1) n/2 (2) -n/2 (3) n/3 (4) -n/3 Solution: Given m, n, r are in HP. So 2/n = (r+m)/mr... View Article
9 Plus 16 By 2 Factorial Plus 27 By 2 Factorial Plus 42 By 4 Factorial To Infinity Is
(1) 11e-4 (2) 11e-6 (3) 10e+5 (4) 3e+4 Solution: 9+16/2! + 27/2! + 42/4! +….∞ Here Tn = (2n2+n+6)/n! Sn... View Article
Tan 70 Tan 50 Plus Tan 20 Tan 20 Are In
(1) AP (2) GP (3) HP (4) None of these Solution: We know tan (A+B) = (tan A+ tan B)... View Article
Log4 2 Log8 2 Plus Log16 2 Plus Is
(1) e2 (2) loge 2 +1 (3) loge 3 -2 (4) 1-loge 2 Solution: We know logb c = 1/logc... View Article
3 By 1 Factorial Plus 5 By 2 Factorial Plus 9 By 3 Factorial To Infinity Is
(1) 4e-1 (2) 4e-3 (3) 3e+2 (4) 3e+4 Solution: Given 3/1! + 5/2! + 9/3! + 15/4 ! + 23/5!... View Article
2 By 3 Factorial Plus 4 By 5 Factorial Plus 6 By 7 Factorial To Infinity Is
(1) e (2) 2e (3) 3e (4) none of these Solution: Given series 2/3! + 4/5! + 6/7! +…..to ∞... View Article
1 2 By 1 Factorial Plus 2 3 By 2 Fact Plus 3 4 By 3 Fact Plus Infinity Is
(1) e (2) 2e (3) 3e (4) none of these Solution: 1.2/1! + 2.3/2! + 3.4/3! +….∞ Tn = n(n+1)/n!... View Article
The Coefficient Of X3 In The Expansion Of 3x Is
(1) 33/6 (2) (log 3)3/3 (3) 3/3! (4) None of these Solution: We know ax = 1+ (x ln a)/1!... View Article
The Expression 1 Plus X2 By 2 Factorial Plus Will Be Represented In Ascending Power Of X As
(1) 1+ 22x2/2! + 24x4/4! + … (2) 1+(2x)2/2! + 22x4/4! + … (3) 1+(2x)2/2.2! + 2x4/4! + … (4)... View Article
The Coefficient Xn Of In The Series 1 Plus A Plus Bx By 1 Factorial Plus
(1) (ab)n/n! (2) eban/n! (3) ea.bn/n! (4) ea+b (ab)n/n! Solution: We know ex = 1 + x/1! + x2/2! +... View Article
