If Log3 2 Log3 2x 5 And Log3 2x 7 By 2 Are In Ap Then X Is Equal To
(1) 2 (2) 3 (3) 4 (4) 2, 3 Solution: Given log3 2, log3 (2x-5) and log3 (2x – 7/2)... View Article
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If Nth Terms Of Two Aps Are 3n Plus 8 And 7n Plus 15 Then The Ratio Of Their 12th Terms Will Be
(1) 4/9 (2) 7/16 (3) 3/7 (4) 8/15 Solution: Let nth term of first AP = 3n+8…(i) First term, a... View Article
If A B C Be In Ap Then A C2 By B2 Ac Equals
(1) 1 (2) 2 (3) 3 (4) 4 Solution: Since a,b,c be in A.P, So 2b = a+c b =... View Article
If The Sum Of N Terms Of An Ap Is Na Plus N2b Where A B Are Constant Then Its Common Difference Will Be
(1) A – B (2) A + B (3) 2A (4) 2B Solution: Given Sn = nA + n2B S1... View Article
If 2x X Plus 8 3x Plus 1 Are In Ap Then The Value Of X Will Be
(1) 3 (2) 7 (3) 5 (4) -2 Solution: Given 2x ,x + 8, 3x + 1 are in A.P... View Article
The Sum Of 24 Terms Of The Following Series Root 2 Plus Root 8 Plus Root 18 Plus Root 32 Is
(1) 300 (2) 300√2 (3) 200√2 (4) none of these Solution: Given series √2 +√8+√18+√32+…. = √2 +2√2 +3√2 +4√2... View Article
If Mth Terms Of The Series 63 Plus 65 Plus 67 Plus 69 Plus And 3 Plus 10 Plus 17 Plus 24 Be Equal Then M Equals
(1) 11 (2) 12 (3) 13 (4) 15 Solution: For the series , 63 + 65 + 67 + 69... View Article
The Sum Of Integers From 1 To 100 That Are Divisible By 2 Or 5 Is
(1) 3000 (2) 3050 (3) 4050 (4) None of these Solution: Required sum = sum of integers divisible by 2... View Article
If Tan N Theta Equal Tan M Theta Then The Different Values Of Theta Will Be In
(1) A.P (2) G.P (3) H.P (4) None of these Solution: Given tan nθ = tan mθ nθ = Nπ+(mθ)... View Article
If The Pth Term Of An Ap Be Q And Qth Term Be P Then Its Rth Term Will Be
(1) p + q + r (2) p + q – r (3) p + r – q (4) p... View Article
The Number Of Terms In The Series 101 Plus 99 Plus 97 Plus 47 Is
(1) 25 (2) 28 (3) 30 (4) 20 Solution: Here a = 101 Common difference, d = 99-101 = -2... View Article
If The Nth Term Of An Ap Be 2n 1 Then The Sum Of Its First N Terms Will Be
(1) n2 -1 (2) (2n – 1)2 (3) n2 (4) n2 + 1 Solution: For AP, an = a+ (n-1)d... View Article
Which Term Of The Sequence 8 Plus 18i 6 Plus 15i 4 Plus 12i Is Purely Imaginary
(1) 5th (2) 7th (3) 8th (4) 6th Solution: Given sequence (-8 + 18i), (-6 + 15i),(-4 + 12i) …….... View Article
If The 9th Term Of An Ap Be Zero Then The Ratio Of Its 29th And 19th Term Is
(1) 1 : 2 (2) 2 : 1 (3) 1 : 3 (4) 3 : 1 Solution: Given 9th term... View Article
The Sequence 5 By Root 7 6 By Root 7 Root 7 Is
(1) HP (2) GP (3) AP (4) None of these Solution: Check the common difference. b-a = (6/√7) – (5/√7)... View Article
The Sum Of The Product Of The Numbers 1 2 N Taken Two At A Time Is
(1) -n(n+1)/2 (2) n(n+1)(2n+1)/6 (3) -n(n+1)(2n+1)/6 (4) 0 Solution: Let a,b,c,…= ± 1, ± 2, ±3… We know (a+b+c)2 =... View Article
23 Dec 2020: UPSC Exam Comprehensive News Analysis
23 Dec 2020 CNA:- Download PDF Here TABLE OF CONTENTS A. GS 1 Related POPULATION 1. Health data shows India... View Article
22 Dec 2020: PIB Summary & Analysis
December 22nd, 2020, PIB:- Download PDF Here TABLE OF CONTENTS 1. Modi receives Legion of Merit Award from US 2.... View Article
22 Dec 2020: The Hindu Analysis
UPSC Current Affairs Preparation: The Hindu Analysis Watch expert analysis of ‘The Hindu’ dated 22nd December 2020. Important news and... View Article
How Do You Factor X 2 X 6
We have to factorise x2 + x – 6 Solution x2 + x – 6 Find two factors of -6... View Article
