What Are The Five Types Of Energy
Energy exists in many forms and they can be converted from one form to another. Although there are many types... View Article
Energy exists in many forms and they can be converted from one form to another. Although there are many types... View Article
We can know if the transistor is NPN or PNP by using a digital multimeter. You can determine if a... View Article
A transistor is an electronic device that is made of semiconductor materials and is used to amplify or electronic signals.... View Article
Solution: Given z = (-√3+3i)(1-i)/(3+√3i)(i)(√3+√3i) Taking √3 outside = √3(-1+√3i)(1-i)/(√3)2(√3+i)(i)(1+i) = (1/√3)(-1+√3i)(1-i)/(-1+i√3)(1+i) = (1-i)/√3(1+i) Multiply numerator and denominator with (1-i)... View Article
Solution: Given 5z2/11z1 is purely imaginary Let us take 5z2/11z1 = iy z2/z1 = 11iy/5 |(2z1+3z2)/(2z1-3z2) = z1(2+3z2/z1)/z1(2-3z2/z1) = (2+3(11iy/5))/(2-3(11iy/3))... View Article
Solution: (1+i)2/(1-i) = (1+i)2(1+i)/(1-i)(1+i) = (1+2i-1)(1+i)/(1–1) = 2i(1+i)/2 = (2i-2)/2 = (-1+i) Conjugate is -1-i. Hence option (4) is the... View Article
The amplitude of sin π/5 + i (1-cos π/5) is (1) 2π/5 (2) π/15 (3) π/10 (4) π/5 Solution: Given... View Article
Solution: Given x+iy = √((a+ib)/(c+id))…(1) Taking conjugate on both sides x-iy = √((a-ib)/(c-id)) ..(2) Multiply (1) and (2) (x+iy )(x-iy)... View Article
Solution: (1-i)/(3+i) +(4i/5) = (5-5i+12i-4)/(3+i)5 = (1+7i)/(3+i)5 Multiply numerator and denominator with (3-i) = (1+7i)(3-i)/(3+i)5(3-i) = (3+21i-i+7)/5(9–1) = (10+20i)/5(10) =... View Article
Solution: Given |Z| – Z = 1 + 2i |Z| = Z +1 + 2i Take Z = x+iy |Z|... View Article
Solution: |Z| + |Z – 1| = |Z| + |-(1-Z )| = |Z| + |1-Z | (since |Z| = |-Z|... View Article
Solution: For any two complex numbers a and b ||a|| ≤|a-b| ||z| -|4/|z| |≤ | z-4/z| => |z| -4/|z| ≤... View Article
Let z and ω be two non zero complex numbers such that |z| = |ω| and Arg z +Arg ω... View Article
Solution: Given z1 = √2(cos π/4 + i sin π/4) z2 = √3(cos π/3 + i sin π/3) |z1| =... View Article
Solution: Given conjugate of (x + iy)(1-2i) is 1 + i. Conjugate of (x + iy)(1-2i) => (x-iy)(1+2i) = 1+i... View Article
Solution: Given |z1| = |z2| + |z1 – z2| |z1| – |z2| = |z1 – z2| Squaring both sides (|z1|... View Article
Convert (i+1)/(cos (π/4)-i sin (π/4) in polar form (1) cos (π/4)+i sin (π/4) (2) cos (π/2)-i sin (π/2)) (3) √2(cos... View Article
Solution: Let z = x+iy Given Re(z) = Im (z) => x = y z2 = (x+iy)2 = x2+2ixy-y2 =... View Article
Solution: Given (1+i)2/(2-i) = x+iy (1+i)2/(2-i) = (1+i)2(2+i)/(2-i)(2+i) = (1+2i-1)(2+i)/(4–1) = 2i(2+i)/5 =( 4i-2)/5 = (-2+4i)/5 x = -2/5 y... View Article
Solution: z = x-iy z1/3 = p + iq x-iy = (p3-3pq2)+i(3p2q-q3) Comparing we get x = p3-3pq2 and y... View Article