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The Modulus Of 1 I 3 I 4i 5 Is

Solution: (1-i)/(3+i) +(4i/5) = (5-5i+12i-4)/(3+i)5 = (1+7i)/(3+i)5 Multiply numerator and denominator with (3-i) = (1+7i)(3-i)/(3+i)5(3-i) = (3+21i-i+7)/5(9–1) = (10+20i)/5(10) =... View Article