Latest Posts

Choose the correct answer among the alternatives given, One mole of ethyl acetate on treatment with an excess of LiAlH4 in dry ether and subsequent acidification produces: (a) 1 mol of acetic acid + 1 mol of ethyl alcohol (b) 1 mol of ethyl alcohol + 1 mole of methyl alcohol (c) 2 mol of ethyl alcohol (d) 1 mol of 2-butanol

Solution: (c) \(\begin{array}{l} CH_{3}COOC_{2}H_{5} \xrightarrow[dryether]{LiAlH_{4}/H_{3}O^{+}} CH_{3}CH_{2}OH + C_{2}H_{5}OH\end{array} \) Ethyl Acetate on treatment with LiAlH4 under go reductions gives 2 moles... View Article