When something travels from one point to the other, this is known as displacement. Presuming the golf ball moves from position x1 to position x2.

position formula is represented as

△x=x2–x1

Where the first position of the body is x1,
the second position after undergoing displacement is x2
the rate of change in the displacement when a change in position takes place is Δx

If the body changes its position after time t the rate of change in position at any moment of time t, x(t) is articulated as,

x(t)=12αt2+v0t+X0

Where,
the position of the body with time t is x(t)
the initial velocity of the body is v0
the acceleration the body possesses is α
the initial position of the body is x0

Position Formula Solved Examples

Problem 1: A person travels 30m distance. Calculate the position of the person at the end time 6s if the initial velocity of the person is 4m/s and angular acceleration is 3 m/s2.

Answer:

Known :
v0  = 4m/s

x0  = 30 m

α  = 3 m/s2

t  = 6s

The change in position of the person at time t is

x(t)=12αt2+v0t+X0

x(6) = 0.5 Ã— 3  Ã— (6)2+ 4 × 6 +  30

X(6) = 54 + 24 + 30

X(6)= 108 m

 

Comments

Leave a Comment

Your Mobile number and Email id will not be published.

*

*