**Position Formula**

When something travels from a point to the other, it is called as displacement. Presuming the golf ball moves from position x_{1} to position x_{2}.

**The position change **Δx** (position formula) is articulated as,**

Where, the first position of the body is x_{1},

the second position after undergoing displacement is x_{2} ,

the rate of change of displacement when change in position takes place is Δx.

If the body changes its position after time t the rate of change in position at any moment of time t, **x(t)** is articulated as,

Where,

the position of the body with respect to time t is x(t) ,

the initial velocity of the body is v0 ,

the acceleration the body possesses is α ,

the initial position of the body is x_{0}.

**Position Formula Solved Examples**

**Let’s examine some sample questions on position:**

**Problem 1: **A boy who has an initial velocity of 3 m/s moves for a distance of 20 m. If it’s angular acceleration is 2 m/s^{2}, compute the position of the boy at the end of 5s.

**Answer:**

Known :

v0 (Intial velocity) = 3m/s,

x0 (distance) = 20 m,

α (angular acceleration) = 2 m/s^{2},

t (time) = 5s

The alteration in position of the boy at instant of time t is articulated as

x(6) = 0.5 × 2 m/s^{2} × (5s)^{2}+ 3 m/s × 5s + 20 m

= 25m + 15m + 20 m

= 60 m.

**Problem 2: **A man at a distance of 6m from his home travels some distance to reach his workplace which is 100 m from his home. Calculate the change in position.

**Answer:**

Known:

x_{1} (First position) = 6 m,

x_{2} (Second position) = 100 m

Change in position is articulated as

Δ x = x_{2 }–_{ }x_{1
}= 100 m – 6m

= 94 m.