# Position Formula

When something travels from one point to the other, this is known as displacement. Presuming the golf ball moves from position x1 to position x2.

position formula is represented as

$\Delta&space;_{x}=x_{2}-&space;x_{1}$

Where the first position of the body is x1,
the second position after undergoing displacement is x2
the rate of change in the displacement when a change in position takes place is Δx

If the body changes its position after time t the rate of change in position at any moment of time t, x(t) is articulated as,

$x(t)=\frac{1}{2}\alpha&space;t^{2}+v_{\circ&space;}t+X_{\circ&space;}$

Where,
the position of the body with time t is x(t)
the initial velocity of the body is v0
the acceleration the body possesses is α
the initial position of the body is x0

Position Formula Solved Examples

Problem 1: A person travels 30m distance. Calculate the position of the person at the end time 6s if the initial velocity of the person is 4m/s and angular acceleration is 3 m/s2.

Known :
v0  = 4m/s

x0  = 30 m

α  = 3 m/s2

t  = 6s

The change in position of the person at time t is

$x(t)=\frac{1}{2}\alpha&space;t^{2}+v_{\circ&space;}t+X_{\circ&space;}$

x(6) = 0.5 × 3  × (6)2+ 4 × 6 +  30

X(6) = 54 + 24 + 30

X(6)= 108 m