# Algebra Formulas For Class 9

Algebra is a part of Mathematics in which general symbols and letters are used to represent quantities and numbers in equations and formulae. There are two parts in algebra – Elementary algebra and Modern algebra (Abstract algebra). Algebra formulas for class 9 include formulas related to algebra identities or expressions.

Algebraic identities chapter is introduced in CBSE class 9. This is a tricky chapter where one needs to learn all the formula and apply them accordingly. To make it easy for them, BYJU’S provide all the formulas on a single page. We believe, algebra formulas for class 9 will help students to score better marks in mathematics.

## List of Algebra Formulas for Class 9

Algebra Formulas List is given below. Have a look at it.

 Algebraic Identities For Class 9 $$\begin{array}{l}(a+b)^{2}=a^2+2ab+b^{2}\end{array}$$ $$\begin{array}{l}(a-b)^{2}=a^{2}-2ab+b^{2}\end{array}$$ $$\begin{array}{l}\left (a + b \right ) \left (a – b \right ) = a^{2} – b^{2}\end{array}$$ $$\begin{array}{l}\left (x + a \right )\left (x + b \right ) = x^{2} + \left (a + b \right )x + ab\end{array}$$ $$\begin{array}{l}\left (x + a \right )\left (x – b \right ) = x^{2} + \left (a – b \right )x – ab\end{array}$$ $$\begin{array}{l}\left (x – a \right )\left (x + b \right ) = x^{2} + \left (b – a \right )x – ab\end{array}$$ $$\begin{array}{l}\left (x – a \right )\left (x – b \right ) = x^{2} – \left (a + b \right )x + ab\end{array}$$ $$\begin{array}{l}\left (a + b \right )^{3} = a^{3} + b^{3} + 3ab\left (a + b \right )\end{array}$$ $$\begin{array}{l}\left (a – b \right )^{3} = a^{3} – b^{3} – 3ab\left (a – b \right )\end{array}$$ $$\begin{array}{l} (x + y + z)^{2} = x^{2} + y^{2} + z^{2} + 2xy + 2yz + 2xz\end{array}$$ $$\begin{array}{l} (x + y – z)^{2} = x^{2} + y^{2} + z^{2} + 2xy – 2yz – 2xz\end{array}$$ $$\begin{array}{l} (x – y + z)^{2} = x^{2} + y^{2} + z^{2} – 2xy – 2yz + 2xz\end{array}$$ $$\begin{array}{l} (x – y – z)^{2} = x^{2} + y^{2} + z^{2} – 2xy + 2yz – 2xz\end{array}$$ $$\begin{array}{l} x^{3} + y^{3} + z^{3} – 3xyz = (x + y + z)(x^{2} + y^{2} + z^{2} – xy – yz -xz)\end{array}$$ $$\begin{array}{l} x^{2} + y^{2} = \frac{1}{2} \left [(x + y)^{2} + (x – y)^{2} \right ]\end{array}$$ $$\begin{array}{l} (x + a) (x + b) (x + c) = x^{3} + (a + b +c)x^{2} + (ab + bc + ca)x + abc\end{array}$$ $$\begin{array}{l} x^{3} + y^{3} = (x + y) (x^{2} – xy + y^{2})\end{array}$$ $$\begin{array}{l} x^{3} – y^{3} = (x – y) (x^{2} + xy + y^{2})\end{array}$$ $$\begin{array}{l} x^{2} + y^{2} + z^{2} -xy – yz – zx = \frac{1}{2} [(x-y)^{2} + (y-z)^{2} + (z-x)^{2}]\end{array}$$

1. Excellent and thank you so so so so much I am so happy

2. (A-b)(A+b)

• (A-b)(A+b)
= A^2-b^2

• (a+b) ^2-2ab

3. Give me mathematics class 9formulas

4. Thx it’s help me a lot

5. Nice
Extremely well

6. perfecto. gracias!