Bernoulli’s principle formulated by Daniel Bernoulli states that as the speed of a moving fluid increases (liquid or gas), the pressure within the fluid decreases. Although Bernoulli deduced the law, it was Leonhard Euler who derived Bernoulli’s equation in its usual form in the year 1752.

Bernoulli’s Principle Bernoulli’s Principle Formula Bernoulli’s Equation Derivation Principle of Continuity Bernoulli’s Principle Use Bernoulli’s Principle Example

## What is Bernoulli’s Principle?

Bernoulli’s principle states that

The total mechanical energy of the moving fluid comprising the gravitational potential energy of elevation, the energy associated with the fluid pressure and the kinetic energy of the fluid motion, remains constant.

Bernoulli’s principle can be derived from the principle of conservation of energy.

## Bernoulli’s Principle Formula

Bernoulli’s equation formula is a relation between pressure, kinetic energy, and gravitational potential energy of a fluid in a container.

The formula for Bernoulli’s principle is given as:

p + \(\frac{1}{2}\) ρ v^{2} + ρgh =constant |

Where,

- p is the pressure exerted by the fluid
- v is the velocity of the fluid
- ρ is the density of the fluid
- h is the height of the container

Bernoulli’s equation gives great insight into the balance between pressure, velocity, and elevation.

**Related Articles:**

## Bernoulli’s Equation Derivation

Consider a pipe with varying diameter and height through which an incompressible fluid is flowing. The relationship between the areas of cross-sections A, the flow speed v, height from the ground y, and pressure p at two different points 1 and 2 is given in the figure below.

**Assumptions:**

- The density of the incompressible fluid remains constant at both points.
- The energy of the fluid is conserved as there are no viscous forces in the fluid.

Therefore, the work done on the fluid is given as:

dW = F_{1}dx_{1} – F_{2}dx_{2}

dW = p_{1}A_{1}dx_{1} – p_{2}A_{2}dx_{2}

dW = p_{1}dV – p_{2}dV = (p_{1} – p_{2})dV

We know that the work done on the fluid was due to conservation of gravitational force and change in kinetic energy. The change in kinetic energy of the fluid is given as:

\(dK = \frac{1}{2}m_{2}v_{2}^{2}-\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}\rho dV(v_{2}^{2}-v_{1}^{2})\)The change in potential energy is given as:

dU = mgy_{2} – mgy_{1} = ρdVg(y_{2} – y_{1})

Therefore, the energy equation is given as:

dW = dK + dU

(p_{1} – p_{2})dV = \(\frac{1}{2}\rho dV(v_{2}^{2}-v_{1}^{2})\)
+ ρdVg(y_{2} – y_{1})

(p_{1} – p_{2}) = \(\frac{1}{2}\rho (v_{2}^{2}-v_{1}^{2})\) + ρg(y_{2} – y_{1})

Rearranging the above equation, we get

\(p_{1}+\frac{1}{2}\rho v_{1}^{2}+\rho gy_{1}=p_{2}+\frac{1}{2}\rho v_{2}^{2}+\rho gy_{2}\)**This is Bernoulli’s equation.**

## Principle of Continuity

According to the principle of continuity

If the fluid is in streamline flow and is in-compressible then we can say that mass of fluid passing through different cross sections are equal.

From the above situation, we can say the mass of liquid inside the container remains the same.

The rate of mass entering = Rate of mass leaving

The rate of mass entering = ρA_{1}V_{1}Δt—– (1)

The rate of mass entering = ρA_{2}V_{2}Δt—– (2)

Using the above equations,

ρA_{1}V_{1}=ρA_{2}V_{2}

This equation is known as the Principle of continuity.

Suppose we need to calculate the speed of efflux for the following setup.

Using Bernoulli’s equation at point 1 and point 2, \(p+\frac{1}{2}\rho v_{1}^{2}+\rho gh=p_{0}+\frac{1}{2}\rho v_{2}^{2}\)\(v_{2}^{2}=v_{1}^{2}+2p-\frac{p_{0}}{\rho }+2gh\)

Generally, A_{2} is much smaller than A_{1}; in this case, v_{1}^{2} is very much smaller than v_{2}^{2} and can be neglected. We then find, \(v_{2}^{2}=2\frac{p-p_{0}}{\rho }+2gh\)

Assuming A_{2}<<A_{1},

We get, v_{2}=\(\sqrt{2gh}\)

Hence, the velocity of efflux is \(\sqrt{2gh}\)

## Bernoulli’s Principle Use

Bernoulli’s principle is used for studying the unsteady potential flow which is used in the theory of ocean surface waves and acoustics. It is also used for approximation of parameters like pressure and speed of the fluid.

The other applications of Bernoulli’s principle are:

**Venturi meter:**It is a device that is based on Bernoulli’s theorem and is used for measuring the rate of flow of liquid through the pipes. Using Bernoulli’s theorem, Venturi meter formula is given as:

\(V=a_{1}a_{2}\sqrt{\frac{2hg}{a_{1}^{2}-a_{2}^{2}}}\) |

**Working of an aeroplane:**The shape of the wings is such that the air passes at a higher speed over the upper surface than the lower surface. The difference in airspeed is calculated using Bernoulli’s principle to create a pressure difference.-
When we are standing on a railway station and a train comes we tend to fall towards the train. This can be explained using Bernoulli’s principle as the train goes past, the velocity of air between the train and us increases. Hence, from the equation, we can say that the pressure decreases so the pressure from behind pushes us towards the train. This is based on the Bernoulli’s effect.

### Relation between Conservation of Energy and Bernoulli’s Equation

Conservation of energy is applied to the fluid flow to produce Bernoulli’s equation. The net work done is the result of a change in fluid’s kinetic energy and gravitational potential energy. Bernoulli’s equation can be modified depending on the form of energy that is involved. Other forms of energy include the dissipation of thermal energy due to fluid viscosity.

### Bernoulli’s Equation at Constant Depth

When the fluid moves at a constant depth that is when h_{1} = h_{2}, then Bernoulli’s equation is given as:

\(P_{1}+\frac{1}{2}\rho v_{1}^{2}=P_{2}+\frac{1}{2}\rho v_{2}^{2}\) |

### Bernoulli’s Equation for Static Fluids

When the fluid is static, then v_{1} = v_{2} = 0, then Bernoulli’s equation is given as:

When v_{1} = v_{2} = 0 |
P_{1} + ρgh_{1} = P_{2} + ρgh_{2} |

When h_{2} = 0 |
P_{2} = P_{1} + ρgh_{1} |

## Bernoulli’s Principle Example

**Q1. Calculate the pressure in the hose whose absolute pressure is 1.01 x 105 N.m-2 if the speed of the water in hose increases from 1.96 m.s-1 to 25.5 m.s-1. Assume that the flow is frictionless and density 10 ^{3} kg.m^{-3}**

**Ans: **Given,

Pressure at point 2, p_{2} = 1.01 × 10^{5} N.m^{-2 }

Density of the fluid, ρ = 10^{3} kg.m^{-3}

Velocity of the fluid at point 1, v_{1} = 1.96 m.s^{-1}

Velocity of the fluid at point 2, v_{2} = 25.5 m.s^{-1}

**From Bernoulli’s principle** for p_{1},

Substituting the values in above equation, we get

\(p_{1}= (1.01\times 10^{5})+\frac{1}{2}(10^{3})[(25.5)^{2}-(1.96)^{2}]\)p_{1} = 4.24 × 10^{5} N.m^{-2}

## FAQs

**Q1. What is Bernoulli famous for?**

Daniel Bernoulli explained how does the speed of fluid affect the pressure of the fluid which is known as Bernoulli’s effect and also explained the kinetic theory of gases. These two were his greatest contribution to Science and these two concepts made him famous.

According to Bernoulli’s effect, he tried to explain that when a fluid flows through a region where the speed increases, the pressure will decrease. Bernoulli’s effects find many real-life applications such as airplanes wings are used for providing a lift to the plane.

good compilation

How to study bernoullis Theorem For A flow of incompressable non-vicous and a streamlined flow of fluid

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