## What is a Carnot Engine?

Carnot engine is a theoretical thermodynamic cycle proposed by **Leonard Carnot**. It gives the estimate of the maximum possible efficiency that a heat engine during the conversion process of heat into work and conversely, working between two reservoirs, can possess. In this section, we will learn about the Carnot cycle and Carnot Theorem in detail.

## Carnot Theorem:

*According to Carnot Theorem:*

Any system working between two given temperatures T

_{1}(hot reservoir) and T_{2}(cold reservoir), can never have an efficiency more than the Carnot engine working between the same reservoirs, respectively.

Also, the efficiency of this type of engine is independent of the nature of the working substance and is only dependent on the temperature of the hot and cold reservoirs.

**Read More:** Carnot’s Theorem

**Similar Reading:**

- Thermodynamics
- Zeroth Law Of Thermodynamics
- First Law Of Thermodynamics
- Second Law Of Thermodynamics
- Third Law Of Thermodynamics

## Carnot Cycle:

A Carnot cycle is defined as an ideal reversible closed thermodynamic cycle in which there are four successive operations involved, which are isothermal expansion, adiabatic expansion, isothermal compression and adiabatic compression. During these operations, the expansion and compression of substance can be done up to the desired point and back to the initial state.

Following are the four processes of the Carnot cycle:

- In (a), the process is reversible isothermal gas expansion. In this process, the amount of heat absorbed by the ideal gas is q
_{in}from the heat source, which is at a temperature of T_{h}. The gas expands and does work on the surroundings. - In (b), the process is reversible adiabatic gas expansion. Here, the system is thermally insulated, and the gas continues to expand and work is done on the surroundings. Now the temperature is lower, T
_{l}. - In (c), the process is reversible isothermal gas compression process. Here, the heat loss q
_{out}occurs when the surroundings do the work at temperature T_{l}. - In (d), the process is reversible adiabatic gas compression. Again the system is thermally insulated. The temperature again rises back to T
_{h}as the surrounding continue to do their work on the gas.

## Steps involved in a Carnot Cycle

*For an ideal gas operating inside a Carnot cycle, the following are the steps involved:*

### Step 1:

**Isothermal expansion:** The gas is taken from P_{1}, V_{1}, T_{1} to P_{2}, V_{2}, T_{2}. Heat Q_{1} is absorbed from the reservoir at temperature T_{1}. Since the expansion is isothermal, the total change in internal energy is zero, and the heat absorbed by the gas is equal to the work done by the gas on the environment, which is given as:

\(W_{1\rightarrow 2}=Q1=\mu \times R\times T_{1}\times ln\frac{v_{2}}{v_{1}}\)

### Step 2:

**Adiabatic expansion:** The gas expands adiabatically from P_{2}, V_{2}, T_{1} to P_{3}, V_{3}, T_{2}.

**Here, work done by the gas is given by:**

\(W_{2\rightarrow 3}=\frac{\mu R}{\gamma -1}(T_{1}-T_{2})\)

### Step 3:

**Isothermal compression:** The gas is compressed isothermally from the state (P_{3}, V_{3}, T_{2}) to (P_{4}, V_{4}, T_{2}).

**Here, the work done on the gas by the environment is given by:**

\(W_{3\rightarrow 4}=\mu RT_{2}ln\frac{v_{3}}{v_{4}}\)

### Step 4:

**Adiabatic compression:** The gas is compressed adiabatically from the state (P_{4}, V_{4}, T_{2}) to (P_{1}, V_{1}, T_{1}).

**Here, the work done on the gas by the environment is given by:**

\(W_{4\rightarrow 1}=\frac{\mu R}{\gamma -1}(T_{1}-T_{2})\)

**Hence, the total work done by the gas on the environment in one complete cycle is given by:**

\(W= W_{1\rightarrow 2}+W_{2\rightarrow 3}+W_{3\rightarrow 4}+W_{4\rightarrow 1}\\ \\ W=\mu \: RT_{1}\: ln\frac{v_{2}}{v_{1}}-\mu \: RT_{2}\: ln\frac{v_{3}}{v_{4}}\)

\(Net\; efficiency =\frac{Net\; workdone\; by\; the\;gas}{Heat\; absorbed\; by\; the\;gas}\)

\(Net\; efficiency =\frac{W}{Q_{1}}=\frac{Q_{1}-Q_{2}}{Q_{1}}=1-\frac{Q_{2}}{Q_{1}}=1-\frac{T_{2}}{T_{1}}\frac{ln\frac{v_{3}}{v_{4}}}{ln\frac{v_{2}}{v_{1}}}\)

Since the step 2–>3 is an adiabatic process, we can write T_{1}V_{2}^{Ƴ-1 }= T_{2}V_{3}^{Ƴ-1}

Or,

\(\frac{v_{2}}{v_{3}}=(\frac{T_{2}}{T_{1}})^{\frac{1}{\gamma -1}}\)

*Similarly, for the process 4–>1, we can write*

\(\frac{v_{1}}{v_{2}}=(\frac{T_{2}}{T_{1}})^{\frac{1}{\gamma -1}}\)

*This implies,*

\(\frac{v_{2}}{v_{3}}=\frac{v_{1}}{v_{2}}\)

**So, the expression for net efficiency of carnot engine reduces to:**

\(Net\; efficiency=1-\frac{T_{2}}{T_{1}}\)

## Frequently Asked Questions – FAQs

### Q1. What is a working fluid in Carnot’s cycle?

### Q2. What is a Carnot heat engine?

### Q3. Name the processes involved in Carnot cycle?

### Q4. What happens in the isothermal expansion process?

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Great

What is the success of the Carnot engine?

Carnot Engine is 64% efficient.

The efficiency of a Carnot heat engine is given by the Formula: 1 – T2/T1, which has been derived above.

Thus the efficiency will completely depend on the temperatures of the source and the sink and is not a constant, However for a given set of source temperature and sink temperature the Carnot heat engine is the most efficient engine possible.

Nice explanation! Thank you!