Maths formulas for class 9

Most of the students of class 9 consider Mathematics subject as a nightmare and maths formulas for class 9 even more difficult to remember. This negative attitude towards one of the major subjects in every field makes them reluctant and lose interest from studies. Many get nervous just before exams and develops a feeling of insecurity. To stay away from these kind of problems, Byju’s brings you 9th class maths formulas pdf and formula list from NCERT books for class 9.

When you are clear with the logic behind every formulas and problems, solving any kind of problem is lot easier. If you are perfect with all the below mentioned formulas that are listed chapter-wise, we assure you that nothing can stop you from scoring maximum marks in class 9 Mathematics examination.

Geometry Shapes Formulas for Class 9

Geometric Figure Area Perimeter 
Rectangle \(A= l \times w\) \(P = 2 \left (l+w \right )\)
Triangle \(A = \frac{1}{2}bh\) \(P = a + b + c\)
Trapezoid A = \(\frac{1}{2} h \left (b_{1}+ b_{2} \right )\) \(P = a + b + c + d\)
Parallelogram \(A = bh\) \(P = 2 (b + h)\)
Circle \(A=\pi r^{2}\) \(C = 2 \pi r\)

Algebraic Identities For Class 9

\((a+b)^{2}=a^2+2ab+b^{2}\)
\((a-b)^{2}=a^{2}-2ab+b^{2}\)
\(\left (a + b \right ) \left (a – b \right ) = a^{2} – b^{2}\)
\(\left (x + a \right )\left (x + b \right ) = x^{2} + \left (a + b \right )x + ab\)
\(\left (x + a \right )\left (x – b \right ) = x^{2} + \left (a – b \right )x – ab\)
\(\left (x – a \right )\left (x + b \right ) = x^{2} + \left (b – a \right )x – ab\)
\(\left (x – a \right )\left (x – b \right ) = x^{2} – \left (a + b \right )x + ab\)
\(\left (a + b \right )^{3} = a^{3} + b^{3} + 3ab\left (a + b \right )\)
\(\left (a – b \right )^{3} = a^{3} – b^{3} – 3ab\left (a – b \right )\)
\( (x + y + z)^{2} = x^{2} + y^{2} + z^{2} + 2xy + 2yz + 2xz\)
\( (x + y – z)^{2} = x^{2} + y^{2} + z^{2} + 2xy – 2yz – 2xz\)
\( (x – y + z)^{2} = x^{2} + y^{2} + z^{2} – 2xy – 2yz + 2xz\)
\( (x – y – z)^{2} = x^{2} + y^{2} + z^{2} – 2xy + 2yz – 2xz\)
\( x^{3} + y^{3} + z^{3} – 3xyz = (x + y + z)(x^{2} + y^{2} + z^{2} – xy – yz -xz\)
\( x^{2} + y^{2} = \frac{1}{2} \left [(x + y)^{2} + (x – y)^{2} \right ]\)
\( (x + a) (x + b) (x + c) = x^{3} + (a + b +c)x^{2} + (ab + bc + ca)x + abc\)
\( x^{3} + y^{3} = (x + y) (x^{2} – xy + y^{2})\)
\( x^{3} – y^{3} = (x – y) (x^{2} + xy + y^{2})\)
\( x^{2} + y^{2} + z^{2} -xy – yz – zx = \frac{1}{2} [(x-y)^{2} + (y-z)^{2} + (z-x)^{2}]\)<

Practise This Question

Find the zeroes of the following quadratic polynomial:
6x2+x5