# RD Sharma Solutions Class 11 Geometric Progressions

## RD Sharma Solutions Class 11 Chapter 20

Geometric progressions (GP) are set of sequence of numbers in which each succeeding number is the product of its previous or preceding number by a constant non-zero called as the common ratio which is denoted by r. The common ratio (r) is calculated by dividing any number in a sequence by the previous or preceding number.

r ≠ 0

For example:

Find the 8th term in the Geometric Progression 1, 3, 9…

a1 = 1, a2 =3, a3=9 and an = 8

Now by applying the formula: r = a2 / a1

We get – 3/1=3.

a8 = a1 r8-1

= (1) (3)7

= (3)7

a8 = 2187

Practice problems on Geometric Progressions through solved RD Sharma solutions to have a better understanding of the topic.

#### Practise This Question

A rectangular paper of length l and breadth h is wrapped around a cylindrical can of radius r and height h.

S1 : The length of rectangular sheet required equals circumference of circle

S2 : The area of rectangular sheet required = 2πrh