RD Sharma Solutions Class 11 Geometric Progressions

RD Sharma Solutions Class 11 Chapter 20

Geometric progressions (GP) are set of sequence of numbers in which each succeeding number is the product of its previous or preceding number by a constant non-zero called as the common ratio which is denoted by r. The common ratio (r) is calculated by dividing any number in a sequence by the previous or preceding number.

r ≠ 0

For example:

Find the 8th term in the Geometric Progression 1, 3, 9…

a1 = 1, a2 =3, a3=9 and an = 8

Now by applying the formula: r = a2 / a1

We get – 3/1=3.

a8 = a1 r8-1

= (1) (3)7

= (3)7

a8 = 2187

Practice problems on Geometric Progressions through solved RD Sharma solutions to have a better understanding of the topic.

 

 


Practise This Question

A student was given the following details while constructing a triangle ABC:

The length of the base of the triangle BC, one of the base angles say B and the sum of the other two sides of the triangle (AB+AC)

He went about the construction of this triangle by first drawing the base of the triangle BC. He then drew an angle at the point B equal to the given angle on a ray that he drew. After completing these steps, he got stuck and doesn’t know what to do next. Which of the following steps will he take up next?