RD Sharma Solutions Class 11 Geometric Progressions

RD Sharma Solutions Class 11 Chapter 20

Geometric progressions (GP) are set of sequence of numbers in which each succeeding number is the product of its previous or preceding number by a constant non-zero called as the common ratio which is denoted by r. The common ratio (r) is calculated by dividing any number in a sequence by the previous or preceding number.

r ≠ 0

For example:

Find the 8th term in the Geometric Progression 1, 3, 9…

a1 = 1, a2 =3, a3=9 and an = 8

Now by applying the formula: r = a2 / a1

We get – 3/1=3.

a8 = a1 r8-1

= (1) (3)7

= (3)7

a8 = 2187

Practice problems on Geometric Progressions through solved RD Sharma solutions to have a better understanding of the topic.



Practise This Question

A rectangular paper of length l and breadth h is wrapped around a cylindrical can of radius r and height h.

S1 : The length of rectangular sheet required equals circumference of circle

S2 : The area of rectangular sheet required = 2πrh