Samacheer Kalvi 8th Maths Book Solutions Term 3 Chapter 5 – Information Processing is available here. The Samacheer Kalvi 8th Maths book answers of Term 3 Chapter 5, available at BYJU’S, contain step by step explanations designed by our mathematics experts. All these important questions are based on the new pattern prescribed by the Tamil Nadu board. Students can also get the solutions of other chapters on samacheer kalvi 8th maths solutions.
Term 3 Chapter 5 of the Samacheer Kalvi 8th Maths guide will help the students to solve problems related to shopping comparison, comparing containers of different size, packing.
Samacheer Kalvi 8th Maths Term 3 Chapter 5: Information Processing Book Exercise 5.1 Questions and Solutions
Question 1: Find the best buy of the following purchases: A pack of 5 chocolate bars for Rs. 175 or 3 chocolate bars for Rs. 114?
Solution:
Item |
Cost per packet |
Number of items in a pack |
Cost of one item |
Chocolate bars |
175 |
5 |
175 / 5 = 35 |
114 |
3 |
114 / 3 = 38 |
Best buy is a pack of 5 chocolate bars for Rs. 175.
Question 2: Using the given picture, find the total special offer price of fresh sweets and bakery products to buy 1 / 2 kg laddu, 1 kg cake, 6 pockets of bread.
Solution:
Product |
Quantity |
Quantity required |
Regular price |
20% offer price |
Special price |
Saving price |
Special price for the cost |
Laddu |
1 kg |
0.5 kg |
245 |
(20 / 100) * 245 = 49 |
245 – 49 – 196 |
49 |
196 * (1 / 2) = 98 |
Chocolate cake |
1 kg |
1 kg |
550 |
(20 / 100) * 550 = 110 |
550 – 110 = 440 |
110 |
440 * 1 = 440 |
Bread |
1 packet |
6 |
20 |
(20 / 100) * 20 = 4 |
20 – 4 = 16 |
4 |
16 * 6 = 96 |
Total |
163 |
634 |
Question 3: When you plan to buy a shirt, one shop offers a discount of Rs. 200 on MRP Rs. 1000 and another shop offers a 15% discount on the same MRP. Where would you buy?
Solution:
Price in the first shop = 1000 – 200 = Rs. 800
Price in the second shop = [85 / 100] * (1000) = Rs. 850
I would buy in Shop I.
Question 4: Amazing park offers a package deal of 5 entrance passes for Rs. 130. If one entrance pass normally costs Rs. 30, how much will you save by taking advantage of this special deal?
Solution:
Cost of one entrance pass = Rs. 30
Cost of 5 entrance passes = 5 * Rs. 30 = Rs. 150
Special deal price = Rs. 30
Amount of saving = 150 – 130 = Rs. 20
Question 5: Suppose you plan to buy 1½ kg of apple, 2 kg of pomegranate, 2 kg of banana, 3 kg of mango, ½ kg of papaya, 3 kg of onion, 1½ kg of tomato, and 1 kg of carrot in shop 1, how much will you save compared to shop 2?
Solution:
Samacheer Kalvi 8th Maths Term 3 Chapter 5: Information Processing Book Exercise 5.2 Questions and Solutions
Question 1: The sizes in MB, for nine computer files, are given below:
53 82 61 38 23 41 16 34 42
The files are to be grouped into folders. Each folder may contain a maximum limit of 100 MB.
(a) Determine the minimum number of folders required.
(b) Use the first-fit method to group the files into folders.
(c) Use the first-fit decreasing method to group the files into folders.
Solution:
(a) Maximum number of folders required = (53 + 82 + 61 + 38 + 23 + 41 + 16 + 34 + 42) / 100 = 3.9 = 4
(b) By the first-fit method
53 82 61 38 23 41 16 34 42 |
Folder 1 |
Folder 2 |
Folder 3 |
Folder 4 |
Folder 5 |
Total size used (MB) |
91 |
98 |
84 |
75 |
42 |
Maximum space of a file (MB) |
100 |
100 |
100 |
100 |
100 |
Remaining space in (MB) |
9 |
2 |
16 |
25 |
58 |
(c) First fit decreasing method
82 42 34 61 41 23 53 38 16 |
Folder 1 |
Folder 2 |
Folder 3 |
Folder 4 |
Total size used (MB) |
98 |
95 |
99 |
98 |
Maximum space of a file (MB) |
100 |
100 |
100 |
100 |
Remaining space in (MB) |
2 |
5 |
1 |
2 |
Question 2: A parcel delivery company has 4 motorcycles. Each motorcycle can carry a maximum load of 30kg. The weights of the parcels, (in kg), in the order they are waiting to be delivered are given below
(a) Determine the minimum number of motorcycles required.
(b) Use the first-fit method to show how the parcels could be allocated to the motorcycles.
(c) Use the first-fit decreasing method to show how the parcels could be allocated to the motorcycles.
Solution:
(a) Maximum number of motorcycles required = (16 + 20 + 8 + 14 + 7 + 6 + 2 + 5 + 12) / 30 = 3
(b) By the first-fit method
16 20 8 14 7 6 2 5 12 |
Motor 1 |
Motor 2 |
Motor 3 |
Motor 4 |
Total weight of the item (in kg) |
30 |
29 |
19 |
12 |
Remaining space (in kg) |
0 |
1 |
11 |
18 |
(c) First fit decreasing method
20 16 14 12 8 7 6 5 2 |
Motor 1 |
Motor 2 |
Motor 3 |
Total weight of the item (in kg) |
30 |
30 |
30 |
Maximum weight carried by motorcycle (in kg) |
30 |
30 |
30 |
Remaining space (in kg) |
0 |
0 |
0 |