JEE Main 2024 Question Paper Solution Discussion Live JEE Main 2024 Question Paper Solution Discussion Live

Dimensions of Potential Difference

Dimensional Formula of Potential Difference

The dimensional formula of potential difference is given by,

[MLT-3 I-1]

Where,

  • M = Mass
  • I = Current
  • L = Length
  • T = Time

Derivation

Potential Difference = work done × [charge]-1 . . . . (1)

Since, Work done = Force (M × a) × Displacement . . . (2)

And, the dimensional formula of,

Mass = [MLT0] . . . . (3)

Displacement = [MLT0] . . . . (4)

Acceleration = [MLT-2] . . . . . (5)

On substituting equation (3), (4) and (5) in equation (2) we get,

Work done = [MLT0] × [MLT-2] × [MLT0]

∴ The dimensions of Work done = [M1 LT-2] . . . . (6)

Since, Charge = Current × time

∴ The dimensional formula of charge = [MLT1 I1] . . . . (7)

On substituting equation (6) and (7) in equation (1) we get,

Potential Difference = work done × [charge]-1

Or, P.D = [M1 LT-2] × [MLT1 I1]-1 = [MLT-3 I-1] .

Therefore, the Potential difference is dimensionally represented as [MLT-3 I-1].

⇒ Check Other Dimensional Formulas:

Test Your Knowledge On Dimensions Of Potential Difference!

Comments

Leave a Comment

Your Mobile number and Email id will not be published.

*

*