JEE Main 2024 Question Paper Solution Discussion Live JEE Main 2024 Question Paper Solution Discussion Live

What Are the Characteristics of Sound Waves?

Introduction to Sound Waves

A sound is a form of energy arising due to mechanical vibrations. Hence, sound waves require a medium for their propagation. Sound cannot travel in a vacuum. Sound waves are propagated as longitudinal mechanical waves through solids, liquids and gases.

Speed of Sound Waves in Solids, Liquid and Gases

Newton’s Formula for Speed of Sound Waves

Newton showed that the speed of sound in a medium

\(\begin{array}{l}v=\sqrt{\frac{E}{P}}\end{array} \)

E = Modulus of elasticity of the medium

P – The density of the medium

Also Read: Wave Motion

Speed of Sound Waves in Solids

\(\begin{array}{l}v=\sqrt{\frac{y}{P}}\end{array} \)

Y = Young’s modulus of the solid

P = Density of the solid

Speed of Sound Waves in Liquid

\(\begin{array}{l}v=\sqrt{\frac{B}{P}}\end{array} \)

B – Bulk modulus of the liquid

P – Density of the liquid

Speed of Sound Waves in Gases

Newton considered the propagation of sound waves through gases as an isothermal process. Absorption and release of heat during compression and rarefaction will be balanced, thus, the temperature remains constant throughout the process. Then, he gave the expression for the velocity of sound in air as

\(\begin{array}{l}v=\sqrt{\frac{P}{\rho }}\end{array} \)

P  is the pressure of the gas (1.1013×105 N/m2)

ρ is the density of the air (1.293 kg/m3)

On substituting the value of pressure and density, the speed of sound obtained was 280 m/s.

There was a huge discrepancy in the speed of sound determined by using this formula with the experimentally determined values. Hence, a correction to this formula was given by Laplace, and it is known as Laplace correction.

Laplace Correction

According to Laplace, the propagation of sound waves in gas takes place adiabatically. So the adiabatic bulk modulus of the gas (γP) has to be used; hence, the speed of sound waves in the gas is

\(\begin{array}{l}V=\sqrt{\frac{\gamma P}{\rho}}\end{array} \)

γP – Adiabatic bulk modulus of the gas

ρ – The density of the medium

For air, γ = 1.41

Substituting the values, the speed of sound value obtained was 331.6 m/s.

The values obtained by the Newton-Laplace formula are in excellent agreement with the experiment results.

Factors Affecting the Speed of Sound in Gases

  • Effect of pressure
  • Effect of temperature
  • Effect of density of the gas
  • Effect of humidity
  • Effect of wind
  • Effect of change in frequency (or) wavelength of the sound wave
  • Effect of amplitude

Effect of Pressure

Suppose the pressure is increased at a constant temperature. Then according to the equation of state PV = RT. If M is the molecular weight and ρ is the density of the gas, then V = M/ρ.

Then, we have

P(M/ρ) = RT

P/ρ = RT/M

At constant temperature, if the pressure changes, then the density also changes in such a way that

P/ρ = Constant

So, a change in pressure does not affect the speed of sound waves through a gas at a constant temperature.

Effect of Temperature

The velocity of sound in a gas

\(\begin{array}{l}v=\sqrt{\frac{\gamma P}{\rho }}\end{array} \)

But PV = RT for a gas and P = RT/V

\(\begin{array}{l}v=\sqrt{\frac{\gamma }{\rho }.\frac{RT}{V}}\end{array} \)

v∝√T

Therefore, the speed of sound is directly proportional to the square root of its absolute temperature.

Effect of Density 

From the velocity of sound in the gas

\(\begin{array}{l}v=\sqrt{\frac{\gamma P}{\rho }}\end{array} \)

The speed of sound is inversely proportional to the square root of the density of the gas.

Effect of Humidity

The density of water vapour is less than that of dry air. The presence of moisture decreases the effective density of air; hence, the sound wave travels faster in moist air or humid air than in dry air.

Effect of Wind

Wind adds its velocity vectorially to that of the sound wave. If the component of Vw of wind speed is in the direction of the sound wave, the resultant speed of sound is

V resultant = V + Vw

Vw – Wind speed

Effect of Change in Frequency or Wavelength of the Sound Wave

Change of frequency or wavelength does not affect the speed of sound in a medium (Homogeneous isotropic medium). Sound travels at the same speed in all directions.

V = λf= Constant

When the sound wave passes from one medium to another medium, the frequency remains constant, but wavelength and velocity change.

Effect of Amplitude

From the velocity relation,

\(\begin{array}{l}v=\sqrt{\frac{\gamma P}{\rho }}\end{array} \)

Generally, the small amplitude does not affect the speed of sound in the gas. However, a very large amplitude may affect the speed of the sound wave.

Related Video

Relation between Speed of Sound in Gas and RMS Speed of Gas Molecules

From the velocity of a sound wave,

\(\begin{array}{l}V\sqrt{\frac{\gamma P}{P}}=\sqrt{\frac{\gamma PV}{M}}\end{array} \)

pv = nRT

n = 1

PV = RT

\(\begin{array}{l}V=\sqrt{\frac{\gamma RT}{M}}\end{array} \)
then rms speed of gas molecules,

\(\begin{array}{l}{{V}_{rms}}=\sqrt{\frac{3RT}{M}}=\sqrt{\frac{3}{P}}\sqrt{\frac{\gamma RT}{M}}=\sqrt{\frac{3}{P}}\,\,V\end{array} \)

\(\begin{array}{l}{{V}_{rms}}=\sqrt{\frac{3}{P}}\,\,V\end{array} \)

Where V is the speed of sound waves through the gas.

Also Read

Frequently Asked Questions on Sound Waves

Q1

Explosions happening on other planets cannot be heard from Earth. Why?

Sound waves require a medium for their propagation. Since it is only a vacuum in space between Earth and the other planets, the sound produced during an explosion cannot be heard from the Earth.

Q2

Why does the flute have many holes?

The flute is an open organ pipe. The length of the air column in it can be changed by covering the holes with fingers. Thus, different frequencies can be produced.

Q3

Sound is produced by vibratory motion, then why cannot we hear any sound from the vibrating pendulum?

The sound we hear has a frequency of 20 Hz to 20,000 Hz. This frequency range is known as the audible range. The frequency of the vibrating pendulum is less than the audible range, and hence it does not produce audible sound.

Q4

There is a time interval between observing a flash of light and hearing thunder. Explain why.

Since the speed of light is much greater than the speed of sound, the flash of light is seen much before hearing thunder.

Test your Knowledge on Sound Waves

Comments

Leave a Comment

Your Mobile number and Email id will not be published.

*

*