 # Class 9 Maths Chapter 15 Probability MCQs

Class 9 Maths Chapter 15 (Probability) MCQs are available here online with answers. The multiple-choice questions given here are based on the CBSE syllabus and the latest NCERT curriculum. Students can practice the chapter-wise questions at BYJU’S and prepare for final exams to score good marks. Also, check Important Questions for Class 9 Maths.

## MCQs on Class 9 Probability

Students of 9th Class can choose the correct answer and thus, solve the MCQs on Probability.

1) The probability of each event, when a coin is tossed for 1000 times with frequencies: Head:455 & Tail: 545 is:

a. 0.455 & 0.545

b. 0.5 & 0.5

c. 0.45 & 0.55

d. 455 & 545

Explanation: Let E and F are the event of the occurrence of Head and Tail, respectively.

Probability of Occurrence of Head P(E) = No. of heads/total number of trials

P(E) = 455/1000 = 0.455

Similarly,

P(F) = No. of tails/total number of trials

P(F) = 545/1000 = 0.545

2) The sum of all probabilities equal to:

a. 4

b. 1

c. 3

d. 2

3) The probability of each event lies between:

a. 1 & 2

b. 1 & 10

c. 0 & 1

d. 0 & 5

4) If P(E) = 0.44, then P(not E) will be:

a. 0.44

b. 0.55

c. 0.50

d. 0.56

Explanation: We know;

P(E) + P(not E) = 1

0.44 + P(not E) = 1

P(not E) = 1 – 0.44 = 0.56

5) If P(E) = 0.38, then probability of event E, not occurring is:

a. 0.62

b. 0.38

c. 0.48

d. 1

Explanation: P(not E) = 1 – P(E) = 1-0.38 = 0.62

6) The probability of drawing an ace card from a deck of cards is:

a. 1/52

b. 1/26

c. 4/13

d. 1/13

Explanation: There are 4 aces in a deck of card.

Hence, the probability of taking one ace out of 52 card = 4/52 = 1/13

7) If the probability of an event to happen is 0.3 and the probability of the event not happening is:

a. 0.7

b. 0.6

c. 0.5

d. None of the above

Explanation: Probability of an event not happening = 1 – P(E)

P(not E) = 1 – 0.3 = 0.7

8) A dice is thrown. The probability of getting 1 and 5 is:

a. ⅙

b. ⅔

c. ⅓

d. ½

Explanation: The probability of getting 1 and 5 = 2/6 = ⅓

9) A batsman hits boundaries for 6 times out of 30 balls. Find the probability that he did not hit the boundaries.

a. ⅕

b. ⅖

c. ⅗

d. ⅘

Explanation: No. of boundaries = 6

No. of balls = 30

No. of balls without boundaries = 30 – 6 =24

Probability of no boundary = 24/30 = ⅘

10. Three coins were tossed 200 times. The number of times 2 heads came up is 72. Then the probability of 2 heads coming up is:

a. 1/25

b. 2/25

c. 7/25

d. 9/25

Explanation: Probability = 72/200 = 9/25

1. sahej

thank you

2. Aman Kumar