The differentiation rules help us to evaluate the derivatives of some particular functions, instead of using the general method of differentiation. The process of differentiation or obtaining the derivative of a function has the significant property of linearity. This property makes the derivative more natural for functions constructed from the primary elementary functions, using the procedures of addition and multiplication by a constant number. Let us learn the differentiation rules with examples in this article.
What are the Differentiation Rules?
The important rules of differentiation are:
- Power Rule
- Sum and Difference Rule
- Product Rule
- Quotient Rule
- Chain Rule
Let us discuss these rules one by one, with examples.
Power Rule of Differentiation
This is one of the most common rules of derivatives. If x is a variable and is raised to a power n, then the derivative of x raised to the power is represented by:
d/dx(xn) = nxn-1
Example: Find the derivative of x5
Solution: As per the power rule, we know;
d/dx(xn) = nxn-1
Hence, d/dx(x5) = 5x5-1 = 5x4
Sum Rule of Differentiation
If the function is sum or difference of two functions, then the derivative of the functions is the sum or difference of the individual functions, i.e.,
If f(x)=u(x)±v(x), then;
f'(x)=u'(x)±v'(x) |
Example 1: f(x) = x + x3
Solution: By applying sum rule of derivative here, we have:
f’(x) = u’(x) + v’(x)
Now, differentiating the given function, we get;
f’(x) = d/dx(x + x3)
f’(x) = d/dx(x) + d/dx(x3)
f’(x) = 1 + 3x2
Example 2:Â Find the derivative of the function f(x) = 6x2 – 4x.
Solution:
Given function is: f(x) = 6x2Â – 4x
This is of the form f(x) = u(x) – v(x)
So by applying the difference rule of derivatives, we get,
f’(x) = d/dx (6x2) – d/dx(4x)
= 6(2x) – 4(1)
= 12x – 4
Therefore, f’(x) = 12x – 4
Product Rule of Differentiation
According to the product rule of derivatives, if the function f(x) is the product of two functions u(x) and v(x), then the derivative of the function is given by:
If f(x) = u(x)×v(x), then:
f′(x) = u′(x) × v(x) + u(x) × v′(x) |
Example: Find the derivative of x2(x+3).
Solution: As per the product rule of derivative, we know;
f′(x) = u′(x) × v(x) + u(x) × v′(x)
Here,
u(x) = x2 and v(x) = x+3
Therefore, on differentiating the given function, we get;
f’(x) = d/dx[x2(x+3)]
f’(x) = d/dx(x2)(x+3)+x2d/dx(x+3)
f’(x) = 2x(x+3)+x2(1)
f’(x) = 2x2+6x+x2
f’(x) = 3x2+6x
f’(x) = 3x(x+2)
Quotient Rule of Differentiation
If f(x) is a function, which is equal to ratio of two functions u(x) and v(x) such that;
f(x) = u(x)/v(x)
Then, as per the quotient rule, the derivative of f(x) is given by;
\(\begin{array}{l}\mathbf{f}^{\prime}(\mathbf{x})=\frac{\mathbf{u}^{\prime}(\mathbf{x}) \times \mathbf{v}(\mathbf{x})-\mathbf{u}(\mathbf{x}) \times \mathbf{v}^{\prime}(\mathbf{x})}{(\mathbf{v}(\mathbf{x}))^{2}}\end{array} \) |
Example: Differentiate f(x)=(x+2)3/√x
Solution: Given,
f(x)=(x+2)3/√x
= (x+2)(x2+4x+4)/√x
= [x3+6x2+12x+8]/x1/2
= x-1/2(x3+6x2+12x+8)
= x5/2+6x3/2+12x1/2+8x-½
Now, differentiating the given equation, we get;
f’(x) = 5/2x3/2 + 6(3/2x1/2)+12(1/2x-1/2)+8(−1/2x-3/2)
= 5/2x3/2 + 9x1/2 + 6x-½ − 4x-3/2
Chain Rule of Differentiation
If a function y = f(x) = g(u) and if u = h(x), then the chain rule for differentiation is defined as;
dy/dx = (dy/du) × (du/dx) |
This rule is majorly used in the method of substitution where we can perform differentiation of composite functions.
Let’s have a look at the examples given below for better understanding of the chain rule differentiation of functions.
Example 1:Â
Differentiate f(x) = (x4 – 1)50
Solution:
Given,
f(x) = (x4Â – 1)50
Let g(x) = x4Â – 1 and n = 50
u(t) = t50
Thus, t = g(x) = x4Â – 1
f(x) = u(g(x))
According to chain rule,
df/dx = (du/dt) × (dt/dx)
Here,
du/dt = d/dt (t50) = 50t49
dt/dx = d/dx g(x)
= d/dx (x4Â – 1)
= 4x3
Thus, df/dx = 50t49 × (4x3)
= 50(x4 – 1)49 × (4x3)
= 200 x3(x4Â – 1)49
Example 2: Â
Find the derivative of f(x) = esin(2x)
Solution:
Given,
f(x) = esin(2x)
Let t = g(x) = sin 2x and u(t) = et
According to chain rule,
df/dx = (du/dt) × (dt/dx)
Here,
du/dt = d/dt (et) = et
dt/dx = d/dx g(x)
= d/dx (sin 2x)
= 2 cos 2x
Thus, df/dx = et × 2 cos 2x
= esin(2x) × 2 cos 2x
= 2 cos(2x) esin(2x)
Related Articles of Differentiation Rules
To learn more about differentiation and differential equations, visit us at BYJU’S. Also, download BYJU’S – The Learning App for interactive videos on maths concepts.
Frequently Asked Questions on Differentiation Rules
What are the basic rules of differentiation?
Power Rule
Sum and Difference Rule
Product Rule
Quotient Rule
Chain Rule
What is the product rule for differentiation?
If f(x) = u(x)×v(x), then f′(x) = u′(x) × v(x) + u(x) × v′(x).
This represents the product rule for differentiation.
What is chain rule in differentiation?
dy/dx = (dy/du) × (du/dx)
Comments