In Calculus, the** product rule** is used to differentiate a function. When a given function is the product of two or more functions, the product rule is used. If the problems are a combination of any two or more functions, then their derivatives can be found by using Product Rule. The derivative of a function h(x) will be denoted by **D {h(x)} or h'(x). **

## Product Rule Definition

The product rule is a general rule for the problems which come under the differentiation where one function is multiplied by another function. The derivative of the product of two differentiable functions is equal to the addition of the first function multiplied by the derivative of the second, and the second function multiplied by the derivative of the first function. The function may be exponential function, logarithmic function, and so on.

## Product Rule Formula

If we have a function y = uv, where u and v are the function of x. Then, by the use of the product rule, we can easily find out the derivative of y with respect to x, and denoted by,

**(dy/dx) = u (dv/dx) + v (du/dx)**

In the first term, taking u as a constant and second term taking v as a constant. The above formula is called the product rule for derivatives.

## Product Rule Proof

Product rule can be proved with the help of limits and by adding, subtracting the one same segment of the function mentioned below:

Let f(x) and g(x) be two functions and h be small increments in the function we get f(x + h) and g(x + h).

Let F(x) = f(x)g(x) and F(x + h) = f(x + h)g(x + h)

Then, the derivative of a function is

\(F'(x)= \lim_{h\rightarrow 0}\frac{F(x+h)-F(x)}{h}\) \(F'(x)= \lim_{h\rightarrow 0}\frac{f(x+h)g(x+h)-f(x)g(x)}{h}\)By adding and subtracting f(x + h)g(x), we get

\(F'(x)= \lim_{h\rightarrow 0}\frac{f(x+h)g(x+h)-f(x+h)g(x)+f(x+h)g(x)-f(x)g(x)}{h}\) \(F'(x)= \lim_{h\rightarrow 0}\frac{f(x+h)(g(x+h)-g(x))+g(x)(f(x+h)-f(x))}{h}\) \(F'(x)= \lim_{h\rightarrow 0}f(x+h)\frac{g(x+h)-g(x)}{h}+g(x)\frac{f(x+h)-f(x)}{h}\) \(F'(x)= \lim_{h\rightarrow 0}f(x+h) \lim_{h\rightarrow 0}\frac{g(x+h)-g(x)}{h}+\lim_{h\rightarrow 0}g(x)\lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}\)By using the definition of a derivative, we get

= f(x + 0) g’ (x) + g(x) f ‘(x)

F'(x) = f(x)g’ (x) + g(x)f ‘(x).

which is the derivative of two functions.

## Product Rule for Different Functions

The product rule for different functions such as derivatives, exponents, logarithmic functions are given below:

**Product Rule for Derivatives:**

For any two functions, say f(x) and g(x), the product rule is D [f(x) g(x)] = f(x) D[g(x)] + g(x) D[f(x)]

d(uv)/dx = u(dv/dx)+ v(du/dx)

where u and v are two functions

**Product Rule for Exponent:**

If m and n are the natural numbers, then x^{n} × x^{m }= x^{n+m.}

Product rule cannot be used to solve expression of exponent having a different base like 2^{3}* 5^{4} and expressions like (x^{n})^{m}. An expression like (x^{n})^{m} can be solved only with the help of Power Rule of Exponents where (x^{n})^{m} = x^{nm}.

**Product Rule for Logarithm:**

For any positive real numbers A and B with the base a

where, a≠ 0, log_{a}AB = log_{a}A + log_{a} B

**Product Rule for Partial Derivatives:**

If we have a function z = f(x,y) g(x,y) and we want to find out the partial derivative of z, then we use the following formula

\(Z_{x}=\frac{\partial z}{\partial x}= g(x,y)\frac{\partial f(x,y)}{\partial x}+f(x,y)\frac{\partial g(x,y)}{\partial x}\) , and \(Z_{y}=\frac{\partial z}{\partial y}= g(x,y)\frac{\partial f(x,y)}{\partial y}+f(x,y)\frac{\partial g(x,y)}{\partial y}\)**Zero Product Rule:**

Zero product rule states, the two non zero numbers is only zero if one of them is zero.If a and b are two numbers then ab = 0 only either a = 0 or b = 0.

if (x-1)x = 0, either x – 1 = 0 or x = 0

It means that if x – 1 = 0, then x = 1

Values of x are 0 and 1. They are also called roots of equation. Mainly used to find the roots of equations, and it works if one side of the equation is zero.

**Triple Product Rule:**

Triple product rule is a generalization of product rule. If f(x) , g(x) and h(x) be three differentiable functions. Then,

D[f(x). g(x). h(x)] = {g(x). h(x)} * D[f(x)] + {f(x). h(x)} * D[g(x)] + {f(x). g(x)} * D[h(x)]

### Product Rule Example

**Example 1: **

Simplify the expression: y= x^{2} × x^{5 }

**Solution:**

Given: y= x^{2} × x^{5 }

We know that the product rule for the exponent is

x^{n} × x^{m }= x^{n+m.}

By using the product rule, it can be written as:

y = x^{2} × x^{5 }= x^{2+5}

y = x^{7}

Hence, the simplified form of the expression, y= x^{2} × x^{5 } is x^{7}.

**Example 2: **

Differentiate y = sin x cos x

**Solution:**

Given: y = sin x cos x

dy/dx = d(sinx cos x)/dx

While differentiating, it becomes

dy/dx = (sin x) [d(cos x)/dx] + (cos x) [d(sin x)/dx]

Differentiate the terms, dy/dx = sin x (-sin x) + cos x (cos x)

dy/dx = -sin^{2.x }+ cos^{2} x

dy/dx =cos^{2}x – sin^{2}x

By using identity,

dy/dx = cos 2x

Therefore, dy/dx = cos 2x

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