The physical quantities which have magnitude, as well as directly attached to them, are known as vectors. Position vectors simply denote the position or location of a point in the three dimensional Cartesian systems with respect to a reference origin. In the upcoming discussion, we shall study about vectors and the Cartesian equation of a plane in three dimensions.
In the previous section we have already discussed that to a given vector there lie infinite planes which are perpendicular to it. But for a particular point there exist one and only one unique plane which is perpendicular to it passing through the given point. The vector equation of a plane in this case is given as
\((\vec{r} – \vec{a}) . \vec{N} = 0\)
Here, Â \(\vec{r} \)
The Cartesian equation of such a plane is represented by:
\(A(x-{x}_{1}) + B (y- {y}_{1}) + C (z -{z}_{1}) = 0 \)
Here, A, B, and C are the direction ratios.
Let us now discuss the equation of a plane passing through three points which are non-collinear.
Equation of a plane passing through three non collinear points
Let us consider three non collinear points P, Q, R lying on a plane such that their position vectors are given by \(\vec{a} \)
The vectors  \(\vec{PQ} \)
(\(\vec{r} \)
Also, from the above figure, Â and . Substituting these values in the above equation, we have
\((\vec{r} – \vec{a}).[(\vec{b}- \vec{a}) × (\vec{c}- \vec{a})] = 0 \)
This represents the equation of a plane in vector form passing through three points which are non- collinear.
To convert this equation in Cartesian system, let us assume that the coordinates of the point P, Q and R are given as (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3) respectively. Also let the coordinates of point A be x, y and z.
Substituting these values in the equation of a plane in Cartesian form passing through three non-collinear points, we have
This is the equation of a plane in Cartesian form passing through three points which are non- collinear.
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