Square and Square Roots Questions

Square and square root questions with solutions are given here for students to practice and memorise the square and square roots of different numbers. Often we have seen students face difficulty memorising the squares and square roots of numbers; one way to remember them could be by solving more and more questions so that they get well familiarised with the concepts of square and square roots.

Learn more about Squares and square roots.

Below is the list of the first 20 perfect squares and square roots:

Number

Perfect Square

Number

Square Root

1

1

1

1

2

4

2

1.4142

3

9

3

1.7321

4

16

4

2

5

25

5

2.2361

6

36

6

2.4495

7

49

7

2.6458

8

64

8

2.8284

9

81

9

3

10

100

10

3.1623

11

121

11

3.3166

12

144

12

3.4641

13

169

13

3.6056

14

196

14

3.7417

15

225

15

3.8730

16

256

16

4

17

289

17

4.1231

18

324

18

4.2426

19

361

19

4.3589

20

400

20

4.4721

Video Lesson on Square of a number

Square and Square Roots Questions with Solutions

Let us solve a few questions based on square and square roots.

Question 1:

Find the difference between the following without actual calculation:

(i) 352 – 342

(ii) 1342 – 1332

(iii) 622 – 612.

Solution:

The difference between the squares of two consecutive natural numbers is the sum of the natural numbers.

(i) 352 – 342 = 35 + 34 = 69

(ii) 1342 – 1332 = 134 + 133 = 267

(iii) 622 – 612 = 62 + 61 = 123

Question 2:

Express the following squares as a sum of two consecutive natural numbers:

(i) 172

(ii) 232

Solution:

The square of any odd natural number m can be expressed as a sum of two consecutive natural numbers: (m2 + 1)/2 and (m2 – 1)/2.

(i) 172 = 289 = [(289 + 1)/2 + (289 – 1)/2] = 145 + 144

(ii) 232.= 529 = [(529 – 1)/2 + (529 + 1)/2] = 264 + 265

Question 3:

Evaluate the following:

(i) 89 × 91

(ii) 16 × 18

Solution:

(i) 89 × 91 = (90 – 1)(90 + 1) = 902 – 1 = 8100 – 1

= 8099

(ii) 16 × 18 = (17 – 1)(17 + 1) = 172 – 1

= 289 – 1

= 288

Question 4:

Find the square root of the following by prime factorisation:

(i) 7744

(ii) 1156

(iii) 1.5625

Solution:

(i) √7744 = √(2 × 2 × 2 × 2 × 2 × 2 × 11 × 11) = 2 × 2 × 2 × 11 = 88

(ii) √1156 = √(2 × 2 × 17 × 17) = 2 × 17 = 34

(iii) √1.5625 = √(15625/10000) = √(5 × 5 × 5 × 5 × 5 × 5)/√(2 × 2 × 2 × 2 × 5 × 5 × 5 × 5)

= (5 × 5 × 5)/ (100) = 1.25

Also, watch these videos to get a clear understanding of square roots and how to visualise them.

Question 5:

Find the square root of 21,25,764 by the long division method.

Solution:

By the long division method:

Square root of 2125764

∴ √2125764 = 1458

Also check: Trick to quickly find square root of any square number.

Question 6:

Find the value of x: √(x × 3042) + √(204.49) = 92.3.

Solution:

First, we shall calculate √(204.49) = √(20449/100) = √(11 × 11 × 13 × 13)/√(100) = 14.3

∴ √(x × 3042) + √(204.49) = 92.3

⇒ √(x × 3042) + 14.3 = 92.3

⇒ √(x × 3042) = 92.3 – 14.3

⇒ √(x × 3042) = 78

Squaring both sides, we get:

3042x = 6084

⇒ x = 2

Question 7:

Find the smallest number by which 10125 must be divided to get a perfect square number. Also, find the square root of the perfect square number.

Solution:

Prime factorisation of 10125 = 5 × 5 × 5 × 9 × 9

We see that one 5 is left unpaired. Thus, 10125 must be divided by 5 to get the perfect square number.

10125 ÷ 5 = 2025

Now, √2025 = √(5× 5 × 9 × 9) = 5 × 9 = 45

Also check:

Question 8:

In an auditorium, there are 21025 chairs. If the number of rows is equal to the number of columns, find out how many rows are there.

Solution:

Total number of chairs = 21025

Let x be the numbers of rows and columns of the chair, respectively.

Then, x × x = 21025

⇒ x2 = 21025

⇒ x = √21025 = 145

∴ there are 145 rows of chairs.

Question 9:

Find the smallest number that should be added to 1290 to make it a perfect square.

Solution:

Now ,1225 = 352 < 1290 < 362 = 1296

We see that, 1290 + 6 = 1296 = 362

Thus, 6 is the smallest number which must be added.

Question 10:

Find a Pythagorean triplet whose one number is 10.

Solution:

We know that for m being a natural number = (m2 – 1, 2m, m2 + 1) is a Pythagorean triplet.

Let 2m = 10

⇒ m = 5

Then, m2 – 1 = 24 and m2 + 1 = 26

Also, 262 = 242.+ 102

∴ (10, 24, 26) is the Pythagorean triplet.

Find more square root questions for practice.

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Practice Questions on Squares and Square Roots

1. Identify which of the following is not a perfect square.

(i) 16000

(ii) 784

(iii) 1000

(iv) 13452

2. Find the Pythagorean triplet, whose one member is 6.

3. Find the square root of the following using the prime factorisation method.

(i) 20164

(ii) 1764

(iii) 3844

4. Find the square of the following using the long division method.

(i) 2030625

(ii) 20736

(iii) 34404

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