The selection of subsets is called a permutation when the order of selection is a factor, while it is called a combination when order is not a factor. Chapter 7Â Permutations and Combinations of Class 11 Maths is categorized under the term â€“ II CBSE Syllabus for 2021-22. Exercise 7.4 of NCERT Solutions for Class 11 Maths Chapter 7- Permutations and Combinations is based on the topic Combination. Students can learn more about the concept by solving the problems given in this exercise.

The NCERT textbook provides plenty of questions for the students to solve and practise. The NCERT Solutions for Class 11 Maths helps the students in understanding the most relevant method of answering a question. This way, the students get a clearer idea of the concept, each time they solve the questions present in the NCERT textbook. Also, students can utilize this resource for the second term exam preparations.

### Download PDF of NCERT Solutions for Class 11 Maths Chapter 7- Permutations and Combinations Exercise 7.4

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### Solutions for Class 11 Maths Chapter 7 â€“ Exercise 7.4

**1. IfÂ ^{n}C_{8}Â =Â ^{n}C_{2}, findÂ ^{n}C_{2.}**

**Solution:**

**2. Determine n if
(i) ^{2n}C_{3:}^{n}C_{3} = 12: 1
(ii) ^{2n}C_{3}: ^{n}C_{3} = 11: 1**

**Solution:**

Simplifying and computing

â‡’Â 4 Ã— (2n â€“ 1) = 12 Ã— (n â€“ 2)

â‡’Â 8n â€“ 4 = 12n â€“ 24

â‡’Â 12n â€“ 8n = 24 â€“ 4

â‡’Â 4n = 20

âˆ´Â n = 5

â‡’Â 11n â€“ 8n = 22 â€“ 4

â‡’Â 3n = 18

âˆ´Â n = 6

**3. How many chords can be drawn through 21 points on a circle?**

**Solution:**

Given 21 points on a circle

We know that we require two points on the circle to draw a chord

âˆ´Â Number of chords is are

â‡’Â ^{21}C_{2}=

âˆ´Â Total number of chords can be drawn are 210

**4. In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?**

**Solution:**

Given 5 boys and 4 girls are in total

We can select 3 boys from 5 boys inÂ ^{5}C_{3}Â ways

Similarly, we can select 3 boys from 54 girls inÂ ^{4}C_{3}Â ways

âˆ´Â Number of ways a team of 3 boys and 3 girls can be selected isÂ ^{5}C_{3}Â Ã—Â ^{4}C_{3}

â‡’Â ^{5}C_{3}Â Ã—Â ^{4}C_{3}Â =

â‡’Â ^{5}C_{3}Â Ã—Â ^{4}C_{3}Â =Â 10Â Ã— 4 = 40

âˆ´ Number of ways a team of 3 boys and 3 girls can be selected isÂ ^{5}C_{3}Â Ã—Â ^{4}C_{3}Â = 40 ways

**5. Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour.**

**Solution:**

Given 6 red balls, 5 white balls and 5 blue balls

We can select 3 red balls from 6 red balls inÂ ^{6}C_{3}Â ways

Similarly, we can select 3 white balls from 5 white balls inÂ ^{5}C_{3}Â ways

Similarly, we can select 3 blue balls from 5 blue balls inÂ ^{5}C_{3}Â ways

âˆ´Â Number of ways of selecting 9 balls isÂ ^{6}C_{3}Â Ã—^{5}C_{3}Â Ã—Â ^{5}C_{3}

âˆ´Â Number of ways of selecting 9 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 3 balls of each colour isÂ ^{6}C_{3}Â Ã—^{5}C_{3}Â Ã—Â ^{5}C_{3}Â = 2000

**6. Determine the number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination.**

**Solution:**

Given a deck of 52 cards

There are 4 Ace cards in a deck of 52 cards.

According to question, we need to select 1 Ace card out the 4 Ace cards

âˆ´Â Number of ways to select 1 Ace from 4 Ace cards isÂ ^{4}C_{1}

â‡’Â More 4 cards are to be selected now from 48 cards (52 cards â€“ 4 Ace cards)

âˆ´Â Number of ways to select 4 cards from 48 cards isÂ ^{48}C_{4}

âˆ´Â Number of 5 card combinations out of a deck of 52 cards if there is exactly one ace in each combination 778320.

**7. In how many ways can one select a cricket team of eleven from 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers?**

**Solution:**

Given 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers

There are 5 players how bowl, and we can require 4 bowlers in a team of 11

âˆ´Â Number of ways in which bowlers can be selected are:Â ^{5}C_{4}

Now other players left are = 17 â€“ 5(bowlers) = 12

Since we need 11 players in a team and already 4 bowlers are selected, we need to select 7 more players from 12.

âˆ´Â Number of ways we can select these players are:Â ^{12}C_{7}

âˆ´Â Total number of combinations possible are:Â ^{5}C_{4}Â Ã—Â ^{12}C_{7}

âˆ´Â Number of ways we can select a team of 11 players where 4 players are bowlers from 17 players are 3960

**8. A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.**

**Solution:**

Given a bag contains 5 black and 6 red balls

Number of ways we can select 2 black balls from 5 black balls areÂ ^{5}C_{2}

Number of ways we can select 3 red balls from 6 red balls areÂ ^{6}C_{3}

Number of ways 2 black and 3 red balls can be selected are ^{5}C_{2}Ã—Â ^{6}C_{3}

âˆ´Â Number of ways in which 2 black and 3 red balls can be selected from 5 black and 6 red balls are 200

**9. In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 specific courses are compulsory for every student?**

**Solution:**

Given 9 courses are available and 2 specific courses are compulsory for every student

Here 2 courses are compulsory out of 9 courses, so a student need to select 5 â€“ 2 = 3 courses

âˆ´Â Number of ways in which 3 ways can be selected from 9 â€“ 2(compulsory courses) = 7 areÂ ^{7}C_{3}

âˆ´Â Number of ways a student selects 5 courses from 9 courses where 2 specific courses are compulsory are: 35

### Access other exercise solutions of Class 11 Maths Chapter 7- Permutations and Combinations

Exercise 7.1 Solutions 6 Questions

Exercise 7.2 Solutions 5 Questions

Exercise 7.3 Solutions 11 Questions

Miscellaneous Exercise On Chapter 7 Solutions 11 Questions

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