NCERT exercise solutions are helpful in improving the hold of the students in the problems related to square and square roots. All the questions of this exercise have been solved by subject experts. NCERT Solutions for Class 8 Maths helps students in enhancing their mathematical skills. Download free Maths NCERT Solutions for Chapter 6 of Class 8, which will help you with the homework as well as the exam preparation.
Download the PDF of NCERT Solutions for Class 8 Maths Chapter 6 – Squares and Square Roots Exercise 6.2
Access Other Exercise Solutions of Class 8 Maths Chapter 6 – Squares and Square Roots
Exercise 6.1 Solutions 9 Questions
Exercise 6.3 Solutions 10 Questions
Exercise 6.4 Solutions 9 Questions
Access Answers of Maths NCERT Class 8 Chapter 6 – Squares and Square Roots Exercise 6.2 Page Number 98
1. Find the square of the following numbers.
i. 32
ii. 35
iii. 86
iv. 93
v. 71
vi. 46
Solution:
i. (32)2
= (30 +2)2
= (30)2 + (2)2 + 2×30×2 [Since, (a+b)2 = a2+b2 +2ab]
= 900 + 4 + 120
= 1024
ii. (35)2
= (30+5 )2
= (30)2 + (5)2 + 2×30×5 [Since, (a+b)2 = a2+b2 +2ab]
= 900 + 25 + 300
= 1225
iii. (86)2
= (90 – 4)2
= (90)2 + (4)2 – 2×90×4 [Since, (a+b)2 = a2+b2 +2ab]
= 8100 + 16 – 720
= 8116 – 720
= 7396
iv. (93)2
= (90+3 )2
= (90)2 + (3)2 + 2×90×3 [Since, (a+b)2 = a2+b2 +2ab]
= 8100 + 9 + 540
= 8649
v. (71)2
= (70+1 )2
= (70)2 + (1)2 +2×70×1 [Since, (a+b)2 = a2+b2 +2ab]
= 4900 + 1 + 140
= 5041
vi. (46)2
= (50 -4 )2
= (50)2 + (4)2 – 2×50×4 [Since, (a+b)2 = a2+b2 +2ab]
= 2500 + 16 – 400
= 2116
2. Write a Pythagorean triplet whose one member is
i. 6
ii. 14
iii. 16
iv. 18
Solution:
For any natural number m, we know that 2m, m2–1, m2+1 is a Pythagorean triplet.
i. 2m = 6
⇒ m = 6/2 = 3
m2–1= 32 – 1 = 9–1 = 8
m2+1= 32+1 = 9+1 = 10
∴ (6, 8, 10) is a Pythagorean triplet.
ii. 2m = 14
⇒ m = 14/2 = 7
m2–1= 72–1 = 49–1 = 48
m2+1 = 72+1 = 49+1 = 50
∴ (14, 48, 50) is not a Pythagorean triplet.
iii. 2m = 16
⇒ m = 16/2 = 8
m2–1 = 82–1 = 64–1 = 63
m2+ 1 = 82+1 = 64+1 = 65
∴ (16, 63, 65) is a Pythagorean triplet.
iv. 2m = 18
⇒ m = 18/2 = 9
m2–1 = 92–1 = 81–1 = 80
m2+1 = 92+1 = 81+1 = 82
∴ (18, 80, 82) is a Pythagorean triplet.
Exercise 6.2 of NCERT Solutions for Class 8 Maths Chapter 6 – Squares and Square Roots is based on the following topics:
- Finding the Square of a Number
- Patterns in squares
- Pythagorean triplets
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