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On dissolving 0.5 g of non-volatile, non-ionic solute to 39 g of benzene, its vapour pressure decreases from 650 mm of Hg to 640 mm of Hg. The depression of freezing point of benzene (in K) upon addition of the solute is __________________. [Given data: Molar mass & molar freezing point depression of benzene is 78 g mol-1 & 5.12 K Kg mol-1]

Answer: (1.03 or 1.02) \(\begin{array}{l}\frac{P^0 – P_S}{P_S} = \frac{n_{solute}}{n_{solvant}}\end{array} \) \(\begin{array}{l}\frac{650 – 640}{640} – \frac{1 \times 0.58 \times 78}{M \times... View Article