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Mass per unit area of a circular disc of radius a depends on the distance r from its centre as σ(r) = A + Br. The moment of inertia of the disc about the axis, perpendicular to the plane and passing through its centre is

a. \(\begin{array}{l}2\pi a^{4}(\frac{A}{4}+\frac{aB}{5})\end{array} \) b. \(\begin{array}{l}2\pi a^{4}(\frac{aA}{4}+\frac{B}{5})\end{array} \) c. \(\begin{array}{l}\pi a^{4}(\frac{A}{4}+\frac{aB}{5})\end{array} \) d. \(\begin{array}{l}2\pi a^{4}(\frac{A}{4}+\frac{B}{5})\end{array} \) Answer: (a) = A... View Article