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Solution Given ar(ΔDRC) = ar(ΔDPC) ar(ΔBDP) = ar(ΔARC) Prove: ABCD and DCPR are trapeziums. Proof: ar(ΔBDP) = ar(ΔARC) ⇒ ar(ΔBDP)... View Article
Literacy rate (in %) 45-55 55-65 65-75 75-85 85-98 Number of cities 3 10 11 8 3 Solution Class Interval... View Article
Solution (a) Since, there are four letters A, B, C and D in a spinning wheel Therefore there are 4... View Article
Solution Given ∠PBC < ∠QCB To Prove PBC < QCB We know that ABC + PBC = 180° So, ABC... View Article
Volume of cube=64cm3 = (side)3 (Side)3 = 64 Side = (64cm3) 1/3 = (2*2*2*2*2*2 cm3)1/3 = 2*2 = 4 cm Hence, Length =... View Article
Given: Q (0, 1) is equidistant from P (5, – 3) and R (x, 6), which means PQ = QR... View Article
Given that ΔABC ~ ΔPQR To Prove AB/PQ = AD/PM Proof We know that the corresponding sides of similar triangles... View Article
In the given figure, let us extend BA to P such that; AP = AC. Now join PC. In ΔAEC,... View Article
Solution The rough sketch of the quadrilateral GOLD can be drawn as follows. (1) ∆ GDL can be constructed by... View Article
∠P + ∠Q = 180° {angles on the same side of transversal} ⇒ ∠P + 130° = 180° ⇒ ∠P... View Article
Given Given that, OA = OC OB = OD and ∠AOB = ∠BOC = ∠OCD = ∠ODA = 90° AC... View Article
Given that S7 = 49 S17 = 289 Find out We need to find the sum of first n terms Solution We... View Article
Let us assume ABCD is a square, where A(-1,2) and B(3,2). And Point O is the point of intersection of... View Article
Solution The rough sketch of the quadrilateral ABCD can be drawn as per the steps given below (1) ∆ABC can... View Article
Solution A rough sketch of the quadrilateral LIFT can be drawn as follows. (1) ∆ ITL can be constructed by... View Article
Solution Given AD = BC and ∠ DAB = ∠ CBA To Prove (i) ΔABD ΔBAC (ii) BD = AC... View Article
Given Dimensions of the matchbox l = 4cm, b = 2.5cm, h = 1.5cm Find out We have to find... View Article
Given The length of the minute hand of a clock is 14 cm Find out To find the Area of the swept... View Article
Solution We know that in-between n2 and (n + 1)2, there exists 2n natural numbers (i) 12 and 13 24 Here, n is... View Article
Given that, ABCD is a rhombus. AC and BD are its diagonals. To Prove AC bisects ∠A as well as... View Article