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-22 |[x]| dx =

1) 1 2) 2 3) 3 4) 4 5) 5 Solution: (4) 4 \(\begin{array}{l}I=\int_{-2}^{2}|[x]| d x=\int_{-2}^{-1}|[x]| d x+\int_{-1}^{0}|[x]| d x+\\... View Article

-π/2π/2 sin |x| dx =

1) 0 2) 1 3) 2 4) π Solution: (3) 2 \(\begin{array}{l}I =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sin |x| d x \\ =-\int_{-\frac{\pi}{2}}^{0} \sin... View Article

-12 |x|3 dx =

1) 5/4 2) 17/4 3) 15/4 4) 4/5 Solution: (2) 17/4 \(\begin{array}{l}\int_{-1}^{2}|x|^{3} =\int_{-1}^{0}|x|^{3}+\int_{0}^{2}|x|^{3} \\ =-\int_{-1}^{0} x^{3}+\int_{0}^{2} x^{3} \\ =-\left[\frac{x^{4}}{4}\right]_{-1}^{0}+\left[\frac{x^{4}}{4}\right]_{0}^{2} \\... View Article