What Is The Feminine Gender Of Pupil
The noun ‘pupil’ is a common gender, which refers to a student Explore more such questions and answers at BYJU’S.
The noun ‘pupil’ is a common gender, which refers to a student Explore more such questions and answers at BYJU’S.
CH3-CH2-OH+SOCl2\(\begin{array}{l} \overset{Pyridine}{\rightarrow}\end{array} \) CH3-CH2-Cl+SO2↑+HCl↑ \(\begin{array}{l} HC \equiv CH + NaNH_{2}\overset{liq.NH3}{\rightarrow}HC\equiv C^{-}Na^{+}\end{array} \) \(\begin{array}{l} CH3-CH2-Cl+HC\equiv C^{-}Na^{+} \rightarrow CH3-CH2-C\equiv CH +NaCl\end{array} \)... View Article
In Microsoft Word or Ms world document, the ruler bar is used as a measuring tool for adjusting indents, the... View Article
The answer is (C) C Compute Optimized instances are the instance designed for the applications that inturn gives the benefit... View Article
Economy is an important part of the UPSC prelims and mains exams; this series titled ‘Economy This Week’ has been initiated to... View Article
UPSC Current Affairs Preparation: The Hindu Analysis Watch expert analysis of ‘The Hindu’ dated 5th Jul 2021. Important news and... View Article
At its zenith, the Delhi Sultanate included states like Bihar, Bengal, Malwa, Gujarat, the Deccan states of Warangal, the Yadavas... View Article
1) 0 2) 2 3) – (1/3) 4) -2 Solution: (2) 2 \(\begin{array}{l}I =\int_{0}^{2}\left|x^{2}-1\right| d x=\int_{0}^{1}\left|x^{2}-1\right| d x+\int_{1}^{2}\left|x^{2}-1\right| d x... View Article
1) 1 2) 2 3) 3 4) 4 5) 5 Solution: (4) 4 \(\begin{array}{l}I=\int_{-2}^{2}|[x]| d x=\int_{-2}^{-1}|[x]| d x+\int_{-1}^{0}|[x]| d x+\\... View Article
1) a 2) 2a 3) 3a 4) 6a Solution: (4) 6a \(\begin{array}{l}\begin{array}{l} I=\int_{0}^{12 a} \frac{f(x)}{f(x)+f(12 a-x)} d x \\ I=\int_{0}^{12... View Article
1) π 2) π/2 3) π/3 4) π/4 Solution: (4) π/4 \(\begin{array}{l}\begin{array}{l} I=\int_{0}^{\frac{\pi}{2}} \frac{\cos x}{\cos x+\sin x} d x \quad... View Article
1) 0 2) 1 3) 2 4) π Solution: (3) 2 \(\begin{array}{l}I =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sin |x| d x \\ =-\int_{-\frac{\pi}{2}}^{0} \sin... View Article
1) 31/2 2) 35/2 3) 47/2 4) 39/2 Solution: (3) 47/2 \(\begin{array}{l}\begin{array}{l} I= \int_{-3}^{2}(|x+1|+|x+2|+|x-1|) d x \\ = \int_{-3}^{+2}|x+1| d... View Article
1) I1 = I2 2) I1 < I2 3) I1 > I2 4) I2 = I1 + π / 4... View Article
1) – π log 2 2) π log 2 3) – π/2 log 2 4) π/2 log 2 Solution: (3)... View Article
1) 5/4 2) 17/4 3) 15/4 4) 4/5 Solution: (2) 17/4 \(\begin{array}{l}\int_{-1}^{2}|x|^{3} =\int_{-1}^{0}|x|^{3}+\int_{0}^{2}|x|^{3} \\ =-\int_{-1}^{0} x^{3}+\int_{0}^{2} x^{3} \\ =-\left[\frac{x^{4}}{4}\right]_{-1}^{0}+\left[\frac{x^{4}}{4}\right]_{0}^{2} \\... View Article
1) π/2 2) 1 3) -1 4) – (π/2) Solution: (4) – (π/2) \(\begin{array}{l}\begin{array}{l} I=\int_{0}^{\pi}[\cot x] d x \\ I=\int_{0}^{\pi}[\cot... View Article
1) 0 2) 2 3) -2 4) -2 < I < 2 Solution: (2) 2 \(\begin{array}{l}\begin{array}{l} I=\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}|\sin x| d x\\... View Article
1) loge 2 < I < π / 4 2) loge 2 > I 3) I = π / 4... View Article
1) I1 = I2 2) 3I1 = I2 3) I1 = 3I2 4) I1 = 5I2 Solution: (3) I1 =... View Article