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Simplify. (2x+5)square -(2x-5)square?

Using the formula \(\begin{array}{l}a^{2}-b^{2}=(a-b)(a+b)\end{array} \) \(\begin{array}{l}(2x+5)^{2}-(2x-5)^{2}= {2x^{2}+2(2x)(5)+5^{2}} – {2x^{2}-2(2x)(5)+5^{2}}\end{array} \) =0+40x+0 =40x