Two different dice are tossed together, find the probability of getting a doublet

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Solution

finding the probability of getting a doublet:
When two dice are tossed together, the total possible outcomes are $= 36$
When the probability is a doublet
The favourable outcomes $= (1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6)$
No.of favorable outcomes $= 6$
Probability of getting doublet $= \frac{6}{36} = \frac{1}{6}$
Therefore the probability of getting doublet is $\frac{1}{6}$

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Similar questions

Two dice are thrown together. Teh probability of getting a doublet is
(a) $\frac{1}{3}$ (b) $\frac{1}{6}$ (c) $\frac{1}{4}$ (d) $\frac{2}{3}$

\frac{1}{3}

\frac{1}{6}

\frac{1}{4}

\frac{2}{3}

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